Phosphoric acid has 3 pKa values (pKa1=2.1, pKa2=6.9, pKa3= 12.4) and after 3 ionization it gives 3 types of ions at different pKa values:
H₃PO₄(aq) + H₂O(l) ⇌ H₃O⁺(aq) + H₂PO₄⁻ (aq) pKₐ₁
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</span>H₂PO₄⁻(aq) + H₂O(l) ⇌ H₃O⁺(aq) + HPO₄²⁻ (aq) pKₐ₂
HPO₄²⁻(aq) + H₂O(l) ⇌ H₃O⁺(aq) + PO₄³⁻ (aq) pKₐ₃
The last equilibrium is associated with the highest pKa value (12.4) of phosphoric acid. There the last OH group will lose its hydrogen and hydrogen phosphate ion (HPO₄²⁻) turns into phosphate ion (PO₄³⁻).
Answer:
2Mg + O2 -> 2MgO
Explanation:
According to the above reaction ,
28.6g(2mole) Mg combine with 32g (1mole) of O2 to give 80.6g (2 mole) of MgO.
thus,
30g Mg will combine with 20g of O2 to produce 50g MgO and 10gO2 will remain unreactive.
I hope it's helpful!
Compression and rarefaction. However instead of crests and troughs, longitudinal waves have compressions and rarefactions. A compression is a region in a longitudinal wave where the particles are closest together. A rarefaction is a region in a longitudinal wave where the particles are furthest apart.
Answer:
In addition, other pollutants like fertilizers, pesticides, and heavy metals are often attached to the soil particles and wash into the water bodies, causing algal blooms and depleted oxygen, which is deadly to most aquatic life.
Answer: The final temperature (T) will be;
16.23°c
Explanation: To find the final temperature of any mixture of substance with an initial temperature use the formula;
M1c(T-T1) + M2c(T-T2)=0
c is the specific heat capacity of the two different substance, but because ice and water are the same, we assume c to be 1
T= final temperature of the mixture
T1= initial temperature of the ice= -10.2°c
T2= initial temperature of the water= 19.7°c
M1= mass of ice= 33.1g
M2= mass of water= 251g
Using the formula above
33.1(T-(-10.2)) + 251(T-19.7)=0
Solving out the bracket
33.1T + 337.62 + 251T - 4944.7 = 0
Collecting like terms to both side of the equation and solving
33.1T + 251T = 4944.7 - 33.62
284.1T = 4607.08
T = 4607.08÷284.1 = 16.23°c
