Answer:
plum pudding model .
Explanation:
the electrons were 'like plums embedded in a pudding'. Also called the Raisin Bread Model.
Answer:
The volume will be 568.89 mL.
Explanation:
Boyle's law says that "The volume occupied by a given gaseous mass at constant temperature is inversely proportional to pressure"
Boyle's law is expressed mathematically as:
Pressure * Volume = constant
or P * V = k
Gay-Lussac's law indicates that when there is a constant volume, as the temperature increases, the pressure of the gas increases. And when the temperature is decreased, the pressure of the gas decreases. That is, the pressure of the gas is directly proportional to its temperature. Gay-Lussac's law can be expressed mathematically as follows:
Where P = pressure, T = temperature, K = Constant
Finally, Charles's law indicates that as the temperature increases, the volume of the gas increases and as the temperature decreases, the volume of the gas decreases. In summary, Charles's law is a law that says that when the amount of gas and pressure are kept constant, the quotient that exists between the volume and the temperature will always have the same value:
Combined law equation is the combination of three gas laws called Boyle's, Charlie's and Gay-Lusac's law:

Studying an initial state 1 and a final state 2, it is fulfilled:

In this case:
- P1= 960 mmHg
- V1= 550 mL
- T1= 200 C= 473 K (being 0 C=273 K)
- P2= 830 mmHg
- V2= ?
- T2= 150 C= 423 K
Replacing:

Solving:

V2= 568.9 mL
<u><em>The volume will be 568.89 mL.</em></u>
Answer:
1.08 g/L is the density of air.
Explanation:
Pressure of the gas = P (atm)
Volume of the gas = V (L)
Moles of gas = n = 
Temperature of the gas = T (K)



where:
D = density of the gas = 
R = universal gas constant
w = Mass of the gas
M =Molar mass of the gas
Given = P = 1.0 atm , T = 54°C = 327.15 K
Average molar mass of the gas = 29 g/mol
Putting all the given values in above equation.


D = 1.08 g/L
1.08 g/L is the density of air.
4-nonanone
Explanation: there is a functional group in the compound CH3CH2CH2CH2CH2COCH2CH2CH3 which is a ketone; So for naming a ketone we must first mention the name of the prefix that is correspond then add the suffix ''one''. And why I putted a ''4'' before the name is because we must indicate where this functional group is located, for doing that we have to start counting where the functional group is the closet to the end of the compound so when looking we should start to count on the right side. this is how I get 4-nonanone