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3 years ago

5

An (blank) determines what will be tested in a scientific experiment

1 answer:

elixir [45]3 years ago

6 0

The answer would be hypotheis since its an theory that isnt proven yet which would involve a scientist to expertiment to make the hypothesis true or valid

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When elemental boron, B, is burned in oxygen gas, the product is diboron trioxide. If the diboron trioxide is then reacted with

zalisa [80]

<u>Answer:</u> The chemical equation is written below.

<u>Explanation:</u>

Every balanced chemical equation follows law of conservation of mass.

This law states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form. This also means that total number of individual atoms on reactant side must be equal to the total number of individual atoms on the product side.

The chemical equation for the reaction of elemental boron and oxygen gas follows:

$4B+3O_2\rightarrow 2B_2O_3$

By Stoichiometry of the reaction:

4 moles of elemental boron reacts with 3 moles of oxygen gas to produce 2 moles of diboron trioxide.

The chemical equation for the reaction of diboron trioxide and water follows:

$B_2O_3+3H_2O\rightarrow 2H_3BO_3$

By Stoichiometry of the reaction:

1 mole of diboron trixoide reacts with 3 moles of water to produce 2 moles of boric acid.

Hence, the chemical equations are written above.

3 0

3 years ago

Two equilibrium reactions of nitrogen with oxygen, with their corresponding equilibrium constants (Kc) at a certain temperature,

7nadin3 [17]

Answer:

Kc = 1.54e - 31 / 2.61e - 24

Explanation:

1 ) $N_{2}(gas) + O_{2}(gas)\rightarrow 2NO(gas)$ ; Kc = 1.54e - 31

2) $N_{2}(gas) + 1/2O_{2}(gas)\rightarrow N_{2}O(gas)$ ; Kc = 2.16e - 24

upon reversing ( 2 ) equation

$N_{2}O(gas)\rightarrow N_{2}(gas) + 1/2O_{2}(gas)$ Kc = 1/2.16e - 24

now adding 1 and reversed equation (2)

$N_{2}(gas) + O_{2}(gas)\rightarrow 2NO(gas)$

$N_{2}O(gas)\rightarrow N_{2}(gas) + 1/2O_{2}(gas)$

we get ,

$N_{2}O(gas) + 1/2O_{2}(gas)\rightarrow 2NO(gas)$ Kc = 1.54e-31 × 1/2.61e - 24

equilibrium constant of equation (3) is -

Kc = 1.54e - 31 / 2.61e - 24

3 0

3 years ago

How do I find molar mass

sergij07 [2.7K]

Answer:The molar mass is the mass of a given chemical element or chemical compound (g) divided by the amount of substance (mol).

The molar mass of a compound can be calculated by adding the standard atomic masses (in g/mol) of the constituent atoms.

Explanation:

7 0

3 years ago

Which of the following demonstrates a double-replacement reaction?

Volgvan

A: Na3PO4 + MnCl2 > Mn3(PO4)2 + NaCl

6 0

3 years ago

Read 2 more answers

Which sequence is an example of radioactive decay?

miss Akunina [59]

I said the equation and that was not answered

5 0

3 years ago