Answer:
the total surface area of the rocket: 1978.2
Step-by-step explanation:
Given that :
- A rocket in the shape of a cone
- The aslant height: 15m
- The base diameter: 12m <=.> Radius: 6m
- The height: 42
So the surface area of a a cone with about the base area because it is attached to a cylinder:
= π*r*l = 3.14*6*15 = 282.6
The area of the cylinder is: 2*π*r*h+pi*
(without the top part of it)
= 2*3.14*6*42 + 3.14*
= 1695.6
At the end, the total surface area of the rocket:
1695.6
+ 282.6
= 1978.2
Answer:
3sqrt2
Step-by-step explanation:
If a side length is a, then a^2 + a^2 = 36
2a^2 = 36
a^2 = 18
a = 3sqrt2
Or, you can remember that in a square, if you cut it in half diagonally, you get a 45-45-90 triangle, so the sidenglth is diagonal/sqrt2
Answer:
166.59 cm³ (approx.)
Step-by-step explanation:
Y=5x
hope this helps you if not plz let me know (:
have a good day
-denis
Answer:
n-p for the first, p-n for the second
Step-by-step explanation: