Well, you can start by putting the slopes and lengths on the right side (Where is says slope of A'B'). The slopes will be the same, so Slope of AB is still 5 and Slope of BC is still 0.25. When you get to the lengths, just multiply it by 1.2. The length for Length of CD is 5.4 and Length of AD is 8.4
Here's what it should look like:
Slope of A'B' ⇔ 5
Slope of B'C' ⇔ 0.25
Length of C'D' ⇔ 5.4
Length of A'D' ⇔ 8.4
Answer: Definitely C (and I'm assuming A since there are 2 answers but I can't see A that well)
Step-by-step explanation: Its not B because B is 7
Its not D because D is 5
Its not E because E is 7
You are looking for -3, so C is the only correct on.
Not sure about A. I can't see it
Answer:
![\displaystyle Yes \\ Range: Set-Builder\:Notation → [f(x)|-2 ≤ f(x) ≤ 4] \\ Interval\:Notation → [-2, 4] \\ \\ Domain: Set-Builder\:Notation → [x|0 ≤ x ≤ 7] \\ Interval\:Notation → [0, 7]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20Yes%20%5C%5C%20Range%3A%20Set-Builder%5C%3ANotation%20%E2%86%92%20%5Bf%28x%29%7C-2%20%E2%89%A4%20f%28x%29%20%E2%89%A4%204%5D%20%5C%5C%20Interval%5C%3ANotation%20%E2%86%92%20%5B-2%2C%204%5D%20%5C%5C%20%5C%5C%20Domain%3A%20Set-Builder%5C%3ANotation%20%E2%86%92%20%5Bx%7C0%20%E2%89%A4%20x%20%E2%89%A4%207%5D%20%5C%5C%20Interval%5C%3ANotation%20%E2%86%92%20%5B0%2C%207%5D)
Step-by-step explanation:
Just by looking at the graph vertically and horisontally, you can tell what the range and domain is, depending on whether the segments are <em>closed</em> or <em>opened</em>.
* This is a function because it passes the <em>vertical</em><em> </em><em>line test</em>.
** This is kind of like a sine wave.
I am joyous to assist you anytime.
Answer: -7
Form your equation. Let x be the number.
6x + 10 = 4x - 4
Solve.
6x + 10 = 4x - 4 Subtract 4x from both sides
2x + 10 = -4 Subtract 10 from both sides
2x = -14 Divide by 2 to both sides
x = -7 Answer!
