Which of the following expressions are equivalent to 6+(-4)-5? (2 answers)

Mathematics

1 answer:

Kipish [7]3 years ago

7 0

Answer: Definitely C (and I'm assuming A since there are 2 answers but I can't see A that well)

Step-by-step explanation: Its not B because B is 7

Its not D because D is 5

Its not E because E is 7

You are looking for -3, so C is the only correct on.

Not sure about A. I can't see it

You might be interested in

Solve the equatuon x/2-(2/(x+1))=1 x=?

Snezhnost [94]

$\frac{x}{2}-\frac{2}{x+1}=1$

We have 2 denominators that we need to get rid of. Whenever there are the denominators, all we have to do is multiply all whole equation with the denominators.

Our denominators are both 2 and x+1. Therefore, we multiply the whole equation by 2(x+1)

$\frac{x}{2}[2(x+1)]-\frac{2}{x+1}[2(x+1)] = 1[2(x+1)]$

Then shorten the fractions.

$\frac{x}{2}[2(x+1)]-\frac{2}{x+1}[2(x+1)] = 1[2(x+1)]\\x(x+1)-2(2)=1(2x+2)$

Distribute in all.

$x^2+x-4=2x+2$

We should get like this. Because the polynomial is 2-degree, I'd suggest you to move all terms to one place. Therefore, moving 2x+2 to another side and subtract.

$x^2+x-4-2x-2=0\\x^2-x-6=0\\$

We are almost there. All we have to do is, solving for x by factoring. (Although there are more than just factoring but factoring this polynomial is faster.)

$(x-3)(x+2)=0\\x=3,-2$