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tekilochka [14]

3 years ago

14

What is the solution to this inequality?

TexFormula1" title="x \div 12 + 3 \leqslant 7" alt="x \div 12 + 3 \leqslant 7" align="absmiddle" class="latex-formula">

1 answer:

Vikki [24]3 years ago

3 0

X/12 + 3 < 7

Subtract 3
x/12 < 4

Multiply by 12
x < 48

Check:
Let x = 0 which is less than or equal to 48

0/12 + 3 < 7
0 + 3 < 7
3 < 7 :)

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The total amount includes principal + interest. The principal was 630 and the total amount was 1083.60.

1083.60 - 630 = 453.60.

Step-by-step explanation:

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4 years ago

4. A salesman has a basic salary and, in addition, recelves a commission which is a fixed percentage of his sales volume, when h

vekshin1

The commission is 20% of sales, the basic salary is $200 and the equation is y = 0.2x + 200

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more variables and numbers.

Let y represent the total sales for x weekly sales, m represent the commision and b represent the basic salary. Hence:

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3 years ago

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3 years ago

A study was designed to investigate the effects of two variables, (1) A student's level of mathematical anxiety and (2) teach

Mashcka [7]

Answer:

$P(X>400)=P(\frac{X-\mu}{\sigma}>\frac{400-\mu}{\sigma})=P(Z>\frac{400-440}{20})=P(z>-2)$

And we can find this probability using the complement rule:

$P(z>-2)=1-P(z$

And in order to find these probabilities we can find tables for the normal standard distribution, excel or a calculator.

$P(z>-2)=1-P(z$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the scores of a population, and for this case we know the distribution for X is given by:

$X \sim N(440,20)$

Where $\mu=440$ and $\sigma=20$

We are interested on this probability

$P(X>440)$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(X>400)=P(\frac{X-\mu}{\sigma}>\frac{400-\mu}{\sigma})=P(Z>\frac{400-440}{20})=P(z>-2)$

And we can find this probability using the complement rule:

$P(z>-2)=1-P(z$

And in order to find these probabilities we can find tables for the normal standard distribution, excel or a calculator.

$P(z>-2)=1-P(z$

6 0

4 years ago