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Gala2k [10]
3 years ago
7

Help me with this hehe

Mathematics
2 answers:
Nonamiya [84]3 years ago
7 0
Can we have the answer choices? I believe it would be 100° but the answer choices would really help :)
sergey [27]3 years ago
6 0
It would be 100 because two parallel lines intersecting make a weird looking x that adds up to 360 so if one side was 80 that means another side was 80 which adds up to 160 so we gotta turn that 160 into a 360 you need 200 more and there are 2 sides left so 200/2 equals 100
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Haley has enlarged a 3-inch by 5-inch picture so that both the length and width are tripled. The area of the enlarged photo is h
77julia77 [94]

Answer:

9 times

Step-by-step explanation:

Area = length x breadth

area of picture not enlarged = 3 x 5 = 15in²

If length is tripled it becomes , 3 x 3 = 9in

If width is tripled, it becomes , 5 x 3 = 15in

Area of enlarged picture = 9in x 15in = 135in²

amount by which enlarged image is larger = 135in² /15in² = 9

5 0
2 years ago
How do you use the distance formula and slope formula to find the lengths of a quadrilateral?
Natasha_Volkova [10]
The distance formula to find the length of the sides... opposite sides equal it could be a rectangle or parallelogram all sides equal, square or rhombus adjacent equal, kite and then the slope is used to check angles if the product of the 2 lines in -1 the lines are perpendicular (right angle) the slopes of 2 lines are the same the sides are parallel. Hope it helps.
5 0
3 years ago
Two right triangles are shown. First, find the missing leg of the triangle on the right. Then you have two lengths to use to fin
jasenka [17]

Answer:

x = 30m

Step-by-step explanation:

<u>GIVEN :-</u>

There are 2 right-angled triangles.

In the triangle on the right side ,

  • Hypotenuse = 26m
  • Base = 10m

In the triangle on the left side ,

  • Base = 18m

<u>TO FIND :-</u>

  • Length of the common perpendicular to both triangles.
  • Length of the hypotenuse of the triangle on the left side.

<u>FACTS TO KNOW BEFORE SOLVING :-</u>

  • Hypotenuse = \sqrt{Base^2 + Perpendicular^2}.
  • Perpendicular = \sqrt{Hypotenuse^2 - Base^2}

<u>SOLUTION :-</u>

In the triangle on the right side ,

Perpendicular = \sqrt{26^2 - 10^2} = \sqrt{676 - 100} = \sqrt{576} = 24m

⇒ Perpendicular of the triangle on right side = Perpendicular of the triangle on left side.

In the triangle on the left side ,

Hypotenuse = \sqrt{24^2 + 18^2} = \sqrt{576 + 324} = \sqrt{900} = 30m

∴ x = 30m

3 0
3 years ago
Evaluate 2.625-(-6)
Lunna [17]
2,625 - (-6) = 

= 2, 625 + 6 

= 8, 625
8 0
3 years ago
What is 8.7x10 (exponent 2 on the ten) in standard form
belka [17]
10 to the exponent 2 is equal to 100, so 8.7 x 100 is equal to 870
4 0
3 years ago
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