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Gala2k [10]
3 years ago
7

Help me with this hehe

Mathematics
2 answers:
Nonamiya [84]3 years ago
7 0
Can we have the answer choices? I believe it would be 100° but the answer choices would really help :)
sergey [27]3 years ago
6 0
It would be 100 because two parallel lines intersecting make a weird looking x that adds up to 360 so if one side was 80 that means another side was 80 which adds up to 160 so we gotta turn that 160 into a 360 you need 200 more and there are 2 sides left so 200/2 equals 100
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Step-by-step explanation:

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Evaluate <br> 9C5<br> and <br> 11P4<br> .
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use the given endpoint r and midpoint m to line rs to find the coordinates of the other endpoint s. r(6,0) m(0,2)
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5 0
3 years ago
Need help please I don’t understand this question
Salsk061 [2.6K]

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a) 9

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5 0
3 years ago
Solve the following differential equation: (1− 5 y +x) dy/dx +y= 5/x −1 .<br><br> C=
Ganezh [65]

Answer:

y(1+x)+x-5\ln xy=C

Step-by-step explanation:

Consider the given differential equation is

(1-\frac{5}{y}+x)\frac{dy}{dx}+y=\frac{5}{x}-1

(1-\frac{5}{y}+x)\frac{dy}{dx}=\frac{5}{x}-1-y

(1-\frac{5}{y}+x)dy=(\frac{5}{x}-1-y)dx

Taking all variables on right sides.

(1-\frac{5}{y}+x)dy-(\frac{5}{x}-1-y)dx=0

(-\frac{5}{x}+1+y)dx+(1-\frac{5}{y}+x)dy=0

Let as assume,

M=-\frac{5}{x}+1+y and N=1-\frac{5}{y}+x

Find partial derivatives \frac{\partial M}{\partial y} and \frac{\partial N}{\partial x}

\frac{\partial M}{\partial y}=1 and \frac{\partial N}{\partial x}=1

Since \frac{\partial M}{\partial y}=\frac{\partial N}{\partial x}, therefore the given differential equation is exact.

The solution of the exact differential equation is

\int Mdx+\int N(\text{without x)}dy=C

\int (-\frac{5}{x}+1+y)dx+\int (1-\frac{5}{y})dy=C

yx-5\ln x+x+y-5\ln y=C

y+x+xy-5\ln x-5\ln y=C

y(1+x)+x-5(\ln x+\ln y)=C

y(1+x)+x-5\ln xy=C

7 0
3 years ago
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