Answer:
The rate of the jet in still air = 1030 miles per hour
And 210 miles per hour is the rate of the stream.
Step-by-step explanation:
Let the speed of the jet in still air be
miles per hour.
And,the speed of the jetstream be
miles per hour.
Key:So when it is moving against the stream speed will be
and when it is moving with the stream, speed will be ![(x+y)](https://tex.z-dn.net/?f=%28x%2By%29)
And we know that.
Distance=Speed multiplied with time.
Arranging the equation.
...equation 1
...equation 2
Working with the equation by using elimination method.
Dividing equation 1 with 8 and equation 2 with 9.We will have
1240=
...eqn 3
820=
...eqn 4
Now adding both the equation will decimate y.
1240+820=2![x](https://tex.z-dn.net/?f=x)
2060=2![x](https://tex.z-dn.net/?f=x)
Dividing with 2 both sides.
1030=![x](https://tex.z-dn.net/?f=x)
By plugging the value of
we can find y in equation 3.
1240=1030 + ![y](https://tex.z-dn.net/?f=y)
Subtracting 1030 from both sides.
1240-1030=![y](https://tex.z-dn.net/?f=y)
=210 miles per hour
So the rate of the jet in still air = 1030 miles per hour
And 210 miles per hour is the rate of the jet stream.