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3 years ago

Fine the value for the following 11 -12÷4+3 (6-2)and0÷21

Mathematics

1 answer:

MrRa [10]3 years ago

4 0

Answer:

1. 20

2. 0

Step-by-step explanation:

1. 20

11 -12÷4+3 (6-2)

Brackets first

11-12÷4+3 x 4

Then division and multiplication

11-3+12

Subtraction next

8+12

Now addition

8+12=20

2. Anything divided by 0 is 0

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Rearrange the formula a2 + b2 = c2 for a. A) a = (c2 − b2)2 B) a = (c2 + b2)2 C) a = c2 − b2 D) a = c2 + b2

madreJ [45]

Answer:

C2 + a2 +2 = b

Would be the new formula

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4 years ago

Read 2 more answers

Pls help me with A, B, C, D

AlekseyPX

Use PEMDAS with the first 3.

a. 3×(6÷5)

3×(1.2) [Parenthesis first]

3.6. [then multiply]

b. 3÷(5×6)

3÷(30) [Parenthesis first]

.1 [then divide]

c. (3×6)÷5

(18)÷5 [Parenthesis first]

3.6 [then divide]

d. 3×6÷5

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8 0

3 years ago

Solve the following equation for x, in terms of a and b. ax = 15 + bx

charle [14.2K]

Value of x will be $x=\frac{15}{a-b}$ .

Equation given in the question → $ax=15+bx$

To find the value of 'x' in terms of a and b, we will simplify the given equation,

$ax=15+bx$

$ax-bx=(15+bx)-bx$

$x(a-b)=15$

$x=\frac{15}{a-b}$

Therefore, Values to filled → Blank 1 = 15

Blank 2 = (a - b)

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brainly.com/question/14318220

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3 years ago

Item 10

storchak [24]

et grass cowbowcowbow

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3 years ago

Find \tan\left(\frac{17\pi}{12}\right)tan( 12 17π )tangent, left parenthesis, start fraction, 17, pi, divided by, 12, end frac

uranmaximum [27]

One way to do this is to notice

$\dfrac{17\pi}{12}=\dfrac\pi6+\dfrac{5\pi}4$

Then

$\tan\dfrac{17\pi}{12}=\tan\left(\dfrac\pi6+\dfrac{5\pi}4\right)=\dfrac{\tan\frac\pi6+\tan\frac{5\pi}4}{1-\tan\frac\pi6\tan\frac{5\pi}4}$

We have

$\tan\dfrac\pi6=\dfrac{\sin\frac\pi6}{\cos\frac\pi6}=\dfrac{\frac12}{\frac{\sqrt3}2}=\dfrac1{\sqrt3}$

and since $\tan x$ has a period of $\pi$ ,

$\tan\dfrac{5\pi}4=\tan\left(\pi+\dfrac\pi4\right)=\tan\dfrac\pi4=1$

and so

$\tan\dfrac{17\pi}{12}=\dfrac{\frac1{\sqrt3}+1}{1-\frac1{\sqrt3}}=\dfrac{1+\sqrt3}{\sqrt3-1}=2+\sqrt3$

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3 years ago

Fine the value for the following 11 -12÷4+3 (6-2)and0÷21​

Fine the value for the following 11 -12÷4+3 (6-2)and0÷21