4 1/2 = 9/2
8 1/4 = 33/4
1/3 x 9/2 = 3/2
1/3 x 33/4 = 33/12
        
             
        
        
        
The math club could rent the room for up to 8 hours. I have also attached a picture of the work in case you need it.
 
        
                    
             
        
        
        
If angle BCD measures 70° then so does angle DBC (because you have formed an isoceles triangle inside the larger ΔABC and the two legs are equal so the two angles have to be equal.   So we have a two 70° angles which leaves 40° for the 3rd angle, which is ∠BDC.   
Since ∠BDC and ∠ADB are supplementary (180°) - that leaves 140° for ∠ADB and is our answer
        
             
        
        
        
<h3>
Answer: 680 different combinations</h3>
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Explanation:
If order mattered, then we'd have 17*16*15 = 4080 different permutations. Notice how I started with 17 and counted down 1 at a a time until I had 3 slots to fill. We count down by 1 because each time we pick someone, we can't pick them again. 
So we have 4080 different ways to pick 3 people if order mattered. But again order doesn't matter. All that counts is the group itself rather than the individual or how they rank. There are 3*2*1 = 6 ways to order any group of three people, which means there are 4080/6 = 680 different combinations possible. 
An alternative is to use the nCr formula with n = 17 and r = 3. That formula is

where the exclamation marks indicate factorials
 
        
             
        
        
        
there are 6 faces multiply 25 by 6
25*6=150cm^2