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3 years ago

Which of the following statements are not true about parallelograms?

Mathematics

1 answer:

Ostrovityanka [42]3 years ago

3 0

9514 1404 393

Answer:

1, 2

Step-by-step explanation:

1. The area of a parallelogram is the product of length and width. The given statement is FALSE.

2. The angles formed by the diagonals are linear pairs, so supplementary. The given statement is FALSE.

3. TRUE

4. TRUE

5. TRUE

Statements 1 and 2 are not true.

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Evaluate : limx→ tan2-sin2x x3

GrogVix [38]

Given:

$\lim _{x\to0}\frac{\tan 2x-\sin 2x}{x^3}$

Solve:

$\lim _{x\to0}\frac{\tan 2x-\sin 2x}{x^3}$

Use l'hopital's rule:

$\begin{gathered} =\lim _{x\to0}\frac{\frac{d}{dx}(-\sin 2x+\tan 2x)}{\frac{d}{dx}(x^3)} \\ =\lim _{x\to0}\frac{-2\cos (2x)+2\tan ^2(2x)+2}{3x^2} \end{gathered}$

Simplify:

$\begin{gathered} =\lim _{x\to0}\frac{-2\cos (2x)+2\tan ^2(2x)+2}{3x^2} \\ =\lim _{x\to0}\frac{2(-\cos (2x)+\tan ^2(2x)+1)}{3x^2} \end{gathered}$

Apply the constant multiple rule:

$\begin{gathered} \lim _{x\to0}cf(x)=c\lim _{x\to0}f(x) \\ \text{With c=}\frac{2}{3} \\ f(x)=\frac{-\cos (2x)+\tan ^2(2x)+1}{x^2} \end{gathered}$ $\begin{gathered} =\frac{2\lim _{x\to0}\frac{-\cos (2x)+\tan ^2(2x)+1}{x^2}}{3} \\ =\frac{2\lim _{x\rightarrow0}\frac{(4\tan ^2(2x)+4)\tan (2x)+2\sin (2x)}{2x}}{3} \end{gathered}$

Similary :

$\begin{gathered} =\frac{2\lim _{x\to0}(2\cos (2x)+12\tan ^4(2x)+16\tan ^2(2x)+4)}{3} \\ =\frac{2(6)}{3} \\ =4 \end{gathered}$

8 0

1 year ago

Mario invested $5100 $ ⁢ 5100 at 13% 13 % to be compounded daily. What will be the value of Mario's investment in 2 2 years? Rou

Gennadij [26K]

Answer:

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Step-by-step explanation:

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3 years ago

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maxonik [38]

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3 years ago

Write an improper fraction whose value is between 5 and 10, and whose denominator is 4

sveta [45]

8/4 should work, because the numerator's higher than the denominator.

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3 years ago

Find the value of x. Leave answers if necessary in the simplest radical form.

shtirl [24]

Answer:

<u>Step-by-step explanation:</u>

cos 45° = base / hypotenuse

1/√2 = base / 15√2

15√2 = base√2

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6 0

3 years ago

Read 2 more answers