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3 years ago

Which of the following statements are not true about parallelograms?

Mathematics

1 answer:

Ostrovityanka [42]3 years ago

3 0

9514 1404 393

Answer:

1, 2

Step-by-step explanation:

1. The area of a parallelogram is the product of length and width. The given statement is FALSE.

2. The angles formed by the diagonals are linear pairs, so supplementary. The given statement is FALSE.

3. TRUE

4. TRUE

5. TRUE

Statements 1 and 2 are not true.

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a woman buys a pair of shoes at a sale.she pays $60,saving $15 on the regular price.The percentage discount on the shoe is

AleksandrR [38]

20% because 75 is the total price and 75 over 15 is 5 and 100 divided by 5 is 20

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3 years ago

the image from reflecting a figure in the fourth quadrant over the y-axis. in what quadrant is the image is

Alekssandra [29.7K]

It should be in the third quadrant

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3 years ago

What is the expectation for a binomial distribution with p = 0.5 and n = 8?

Natasha2012 [34]

Answer: 4

Step-by-step explanation:

Given the following :

P = probability of success = 0.5

n = number of trials = 8

The expected value of a binomial distribution with probability of success P and number of trials n is defined by:

E(n, p) = n * p

Therefore, expected value when P = 0.5 and n = 8

E(8, 0.5) = 8 × 0.5

= 4

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8 0

3 years ago

A physics exam consists of 9 multiple-choice questions and 6 open-ended problems in which all work must be shown. If an examinee

katrin [286]

Answer: A) 1260

Step-by-step explanation:

We know that the number of combinations of n things taking r at a time is given by :-

$^nC_r=\dfrac{n!}{(n-r)!r!}$

Given : Total multiple-choice questions = 9

Total open-ended problems=6

If an examine must answer 6 of the multiple-choice questions and 4 of the open-ended problems ,

No. of ways to answer 6 multiple-choice questions

= $^9C_6=\dfrac{9!}{6!(9-6)!}=\dfrac{9\times8\times7\times6!}{6!3!}=84$

No. of ways to answer 4 open-ended problems

= $^6C_4=\dfrac{6!}{4!(6-4)!}=\dfrac{6\times5\times4!}{4!2!}=15$

Then by using the Fundamental principal of counting the number of ways can the questions and problems be chosen = No. of ways to answer 6 multiple-choice questions x No. of ways to answer 4 open-ended problems

= $84\times15=1260$

Hence, the correct answer is option A) 1260

5 0

3 years ago

The question is in the image.

miskamm [114]

Step-by-step explanation:

f(x) = 4x + 1

g(x) = x² - 5

(f+g)(x) = f(x) + g(x)

= (4x + 1) + (x² - 5)

= x² + 4x + (1 - 5)

= x² + 4x - 4

Option → C

7 0

2 years ago