Hey there!
When factoring trinomials, we're usually looking at the trinomial in the format of:
ax^2 + bx + c
In order to factor these, we have to use a different method than when a<1. When a is less than one, we can simply figure out the factors that add to the middle term and multiply to the last, but here we have to do a little something different.
The first step is to factor out the GCD of these terms. As you can see, there isn't one, as 13 is prime.
The next step is to multiply a by c:
6(6) = 36
Next, we have to, using the pattern of trinomials(the two binomials would have factors that add to the middle term and multiply to the last), we have to find factors of 36 that multiply to 36 and add to -13. When we do this step, we can disregard the last term for now. Let's list factors of 36:
36 =
18, 2 = 20
9,4 = 13
-9, -4 = 13
-9 and -4 work for this. We can now write them as x terms and factor by grouping:
6m^2 - 4m - 9m + 6 (don't forget that last term)
For the left side, factor out a 2m:
2m(3m - 2)
For the right side, factor out a -3:
2m(m-2) - 3(m-2)
Now that we have our common factor of m-2, we can write them as a product of 2 binomials:
(2m-3)(m-2)
Hope this helps!
17 is next in the pattern
Answer:
here domain is x and range is 49
Answer:
ok so I think it's -3:3
Step-by-step explanation:
hopefully thats right
Answer:
Step-by-step explanation:
The parametric equations of a circle is
and 
The radius of the unit circle is 1 unit.
This implies that any point on the unit circle is represented by:
and 
where 
is the angle in standard position,
From the question, the given angle in standard position is 
.
This angle intersects the unit circle at 
But
We substitute 
and
This implies that:
