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MrRissso [65]
2 years ago
7

7.3 reteaching with practice 415-420

Mathematics
1 answer:
Alik [6]2 years ago
8 0
5. Y,45 is the axial amount of the y axis items 5
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Jason’s budget is shown in the circle graph below. His total monthly budget is $3,000. How much does Jason spend on groceries? A
bonufazy [111]

Answer:

D.$750

Step-by-step explanation:

3000 x 0.25 = 750

8 0
4 years ago
Read 2 more answers
(x-h)^2+(y-k)^2=r^2
dimaraw [331]

Answer:

(x-2)^2 + (y - 5)^2 = 16

Step-by-step explanation:

Given the standard form of an equation of a circle

(x-h)^2+(y-k)^2=r^2

If (h, k) = (5,2) and r = 4

Substitute

(x-2)^2 + (y - 5)^2 = 4^2

(x-2)^2 + (y - 5)^2 = 16

Hence the required equation is (x-2)^2 + (y - 5)^2 = 16

7 0
3 years ago
(problem 83)
AVprozaik [17]

To find the derivative of this function, there is a property that we should know called the Constant Multiple Rule, which says:

\dfrac{d}{dx}[cf(x)] = cf'(x) (where c is a constant)


Remember that the derivative of \csc(x) is -\csc(x)\cot(x). However, you may notice that we are finding the derivative of \dfrac{1}{2}\csc(2x), not \dfrac{1}{2} \csc(x). So, we are going to have to use the chain rule. To complete the chain rule for the derivative of a trigonometric function (in layman's terms) is basically the following: First, complete the derivative of the trig function as you would if what was inside the trig function is x. Then, take the derivative of what's inside of the trig function and multiply it by what you found in the first step.


Let's apply that to our problem. Right now, I am not going to worry about the \dfrac{1}{2} at the front of the equation, since we can just multiply it back in at the end of our problem. So, let's examine \csc(2x). We see that what's inside the trig function is 2x, which has a derivative of 2. Thus, let's first find the derivative of \csc(2x) as if 2x was just x and then multiply it by 2.


The derivative of \csc(2x) would first be -\cot(2x)\csc(2x). Multiplying it by 2, we get our derivative of -2\cot(2x)\csc(2x). However, don't forget to multiply it by the \dfrac{1}{2} that we removed near the beginning. This gives us our final derivative of -\cot(2x)\csc(2x).


Remember that we now have to find the derivative at the given point. To do this, simply "plug in" the point into the derivative using the x-coordinate. This is shown below:

-\cot[2(\dfrac{\pi}{4})]\csc[2(\dfrac{\pi}{4})]

-\cot(\dfrac{\pi}{2})\csc(\dfrac{\pi}{2})

-(0)(1) = \boxed{0}


Our final answer is 0.

3 0
3 years ago
Which ordered pair makes both inequalities true?y > –2x 3y < x – 2?
grin007 [14]
Whatever your choices are, just substitute the x and y values to the equations. If they satisfy the inequality, then they are the solutions. For example, point (7, 1) satisfies the inequalities.

y > -2x
1 > -2(7)
1 > -14 (true)

<span>3y < x – 2
3(1) < 7 - 2
3 < 5 (true)

I hope I was able to help you. Have a good day.</span>
3 0
3 years ago
PLEASE HELP ME RIGHT ANSWERS ONLY Your gas-powered weed trimer has a tank that holds 0.72 gallons. If you burn 0.13 gallons ever
sergeinik [125]

Answer:

sorry I don't understand your question

8 0
3 years ago
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