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2 years ago

What is the quotient of 4.8 divided by -0.4

Mathematics

1 answer:

Fynjy0 [20]2 years ago

8 0

the answer of division is 5.2

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Which equation has a constant of proportionality equal to

seraphim [82]

There are many equations that has a constant of

proportionality, might want to make it more specific.

5 0

3 years ago

The value of y varies directly with x. If x=4, then y=10. a. Find the constant of proportionality. b. Write an equation to repre

Lynna [10]

Answer:

aaaa

Step-by-step explanation:

In a short paragraph, describe how you would determine the amount of work needed to pull a toboggan the length of a football field. Be sure to include the equipment list and describe the measurements that you will take.

3 0

3 years ago

-105=7(1+2n)<br> A:-8<br> B-4<br> C-10<br> D:-9<br> What’s the value of n in this equation?

Marat540 [252]

The answer is -8 or a

7 0

3 years ago

Find the perimeter of pentagon STUVW WITH VERTICES S(0,0) T(3,-2) U(2,-5) V(-2,-5) W(-3,-2)

andrew11 [14]

Use the distance formula.

$\sqrt{( x_{2} - x_{1} )^2 + (y_{2} - y_{1})^2}$

Points S and W.
$\sqrt{(3)^2 + (2)^2}$

$\sqrt{9+4}$

$\sqrt{13}$

~3.6

Points S and T
$\sqrt{(3 - 0)^2 + (-2 - 0)^2}$

$\sqrt{(3)^2 + (-2)^2}$

$\sqrt{9+4}$

$\sqrt{13}$

~3.6

Points T and U
$\sqrt{(3 - 2)^2 + (-2 + 5)^2}$

$\sqrt{(1)^2 + (3)^2}$

$\sqrt{1+9}$

$\sqrt{10}$

~3.1

Points U and V
$\sqrt{(2+2)^2 + (-5 + 5)^2}$

$\sqrt{(4)^2 + (0)^2}$

$\sqrt{16}$

~4

Points V and W
$\sqrt{(-2+3)^2 + (-5 + 2)^2}$

$\sqrt{(1)^2 + (-3)^2}$

$\sqrt{2+9}$

$\sqrt{11}$

~3.3

Add all these together.

3.3 + 3.1 + 4 + 3.1 + 3.6
≈17

4 0

3 years ago

Solve the system of linear equations using the elimination method x=3y;3x-2y=14

vladimir1956 [14]

Answer:

Step-by-step explanation:

$\left\{\begin{array}{ccc}x=3y&\text{subtract}\ 3y\ \text{from both sides}\\3x-2y=14\end{array}\right\\\\\left\{\begin{array}{ccc}x-3y=0&\text{multiply both sides by (-3)}\\3x-2y=14\end{array}\right\\\underline{+\left\{\begin{array}{ccc}-3x+9y=0\\3x-2y=14\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad\qquad7y=14\qquad\text{divide both sides by 7}\\.\qquad\qquad y=2\\\\\text{put the value of y to the first equation:}\\x=3(2)=6$

7 0

3 years ago