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pogonyaev
2 years ago
8

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Mathematics
1 answer:
BigorU [14]2 years ago
5 0

Answer:

a) ∠XWY = 53°

b) ∠XZY = 106°

Step-by-step explanation:

The relationship between the central angle and the arc length is that they're equal. So, if arc XY = 106° this means that ∠XZY = 106°.

The relationship between the central angle ∠XZY and the inscribed angle ∠XWY is that the inscribed angle is half the value of the central one.

So, ∠XWY= ∠XZY/2 = 106/2 = 53

<u>Results:</u>

∠XWY = 53°

∠XZY = 106°

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What property of operations can be used to justify that the two expressions in this equation are equivalent? 6x^2 +4x=4x + 6x^2
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Answer:

Commutative

Step-by-step explanation:

There are four basic property of operations to solve an algebraic expressions. They are associative, commutative, distributive and identity.

The expression given is : $6x^2 + 4x=4x+6x^2$

So the given algebraic expression is a commutative property of operations. The commutative property states that when any two numbers are added in an expression the sum of the numbers are the same regardless of the order of the numbers that are added.

Thus the sum of the above expression will be same in which ever order the numbers are added.

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2 years ago
A-5-b; use a =10 and b =4
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Answer:

1

Step-by-step explanation:

10-5-4 = 1

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3 years ago
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David and Lacey are 2000 feet apart on a coastline. They each look at the same boat in the water. The angle between the coastlin
Ulleksa [173]

By using the given distances and directions, we have;

Part A: 1083.5 feet

Part B: 1921.37 feet

Part C: 58.05°

<h3>How can the distances and directions be calculated?</h3>

The distance between David and Lacey = 2000 feet

David's angle to the boat = 70°

Lacey's angle to the boat = 32°

Part A

The distance of the boat from David is found as follows;

Imaginary lines drawn from the boat to David and then to Lacey form a triangle.

In the triangle, let <em>A</em><em> </em>= 70°

B = 32°

Therefore by the sum of angles in a triangle, we have;

C = 180° - (70° + 32°) = 78°

By using sine rule we have;

\frac{a}{sin(A)}  =  \frac{b}{sin( B )} =   \frac{c}{sin(C)}

David's distance from the boat, <em>b</em>, is therefore;

\frac{b}{sin( 32 )} =   \frac{2000}{sin(78)}

The angle subtended by the coastline, <em>C</em>, is therefore;

b =   \frac{2000}{sin(78)}  \times sin( 32 ) = 1083.5

  • David's distance from the boat is 1083.5 feet

Part B

The distance between the boat and Lacey is found as follows;

\mathbf{ \frac{a}{sin( 70)} }=   \frac{2000}{sin(78)}

a =   \frac{2000}{sin(78)}  \times sin( 70 ) = 1921.37

  • Lacey's distance from the boat is 1921.37 feet

Part C

When <em>b </em>= 1200 feet, we have;

Finding the vertical distance of the boat from the coastline, we have;

1083.5 × sin(70) = 1018.17

We have;

\frac{1200}{sin(90)}  =  \frac{1018.17}{sin( B' )}

{sin( B' )} = \frac{sin(90)}{1200} \times 1018.17

The angle between the coastline and his view to the boat, <em>B'</em>, is therefore;

  • B' = arcsine (1018.17÷1200) = 58.05°

Learn more about sine rule here:

brainly.com/question/4372174

#SPJ1

4 0
1 year ago
Mr.giarmo left his home to travel to work at 7:15a.m. 25 minutes later he arrived at work whay time did Mr hiarmo arrive at work
Tanzania [10]
15+25= 40
Mr. Giarmo arrived at work at 7:40 a.m.
5 0
3 years ago
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