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TEA [102]
3 years ago
13

So i need help with the question below.

Mathematics
1 answer:
Shkiper50 [21]3 years ago
8 0

Answer:

Option (1)

Step-by-step explanation:

Option (1)

3\frac{3}{9}+7\frac{6}{11}=10\frac{87}{99}

3\frac{3}{9}+7\frac{6}{11} =3+\frac{3}{9}+7+\frac{6}{11}

             =(3+7)+(\frac{3}{9}+\frac{6}{11})

             =10+(\frac{3}{9}\times \frac{11}{11})+(\frac{6}{11}\times \frac{9}{9})

             =10+(\frac{33}{99}+\frac{54}{99})

             =10+\frac{87}{99}

             =10\frac{87}{99}

True.

Option (2)

2\frac{3}{8}+6\frac{4}{5}=8\frac{12}{40}

2\frac{3}{8}+6\frac{4}{5}=2+\frac{3}{8}+6+\frac{4}{5}

             =(2+6)+(\frac{3}{8}+\frac{4}{5})

             =(8)+(\frac{3}{8}\times \frac{5}{5} +\frac{4}{5}\times \frac{8}{8})

             =8+(\frac{15}{40}+\frac{32}{40})

             =8+\frac{47}{40}

             =8+\frac{40}{40}+\frac{7}{40}

             =8+1+\frac{7}{40}

             =9+\frac{7}{40}

             =9\frac{7}{40}

False.

Option(3)

3\frac{3}{7}+4\frac{2}{3}=7\frac{2}{21}

3\frac{3}{7}+4\frac{2}{3}=(3+\frac{3}{7})+(4+\frac{2}{3})

             =(3+4)+(\frac{3}{7}+\frac{2}{3})

             =7+(\frac{3}{7}\times \frac{3}{3} +\frac{2}{3}\times \frac{7}{7})

             =7+(\frac{9}{21}+\frac{14}{21})

             =7+(\frac{23}{21})

             =7+(\frac{21}{21}+\frac{2}{21})

             =8+\frac{1}{21}

             =8\frac{1}{21}

False.

Option (4)

4\frac{5}{6}+5\frac{5}{7}=9\frac{10}{13}

4\frac{5}{6}+5\frac{5}{7}=4+\frac{5}{6}+5+\frac{5}{7}

             =(4+5)+(\frac{5}{6}+\frac{5}{7})

             =9+(\frac{5}{6}\times \frac{7}{7}+\frac{5}{7}\times \frac{6}{6})

             =9+(\frac{35}{42}+\frac{30}{42})

             =9+\frac{65}{42}

             =9+(\frac{42}{42}+\frac{23}{42})

             =9+1+\frac{23}{42}

             =10\frac{23}{42}

False.

Therefore, Option (1) is the answer.

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Step-by-step explanation:

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Step-by-step explanation:

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5 0
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Read 2 more answers
The product of two consecutive integers is 5 more than three time the larger. What are the integers?
kvasek [131]
When calculating consecutive integers, the smaller number is x and the larger number is (x + 1).
So the equation you can use is x + (x + 1) = 5 + 3(x + 1)
This is because the sum of the consecutive integers are equal to 5 more than 3 times the larger integer.
Now simplify:
x + (x + 1) = 5 + 3(x + 1)
2x + 1 = 5 + 3(x + 1)
2x + 1 = 5 + 3x + 3
2x + 1 = 3x + 8
Now isolate the variable:
2x + 1 = 3x + 8
Subtract 2x from both sides:
1 = x + 8
Subtract 8 from both side:
-7 = x
x = -7
So the smaller number is -7 and the larger number is -6.

Now check your answer:
-7 + (-7 + 1) = 5 + 3(-7 + 1)
-7 + (-6) = 5 + 3(-7 + 1)
-7 + (-6) = 5 + 3(-7 + 1)
-7 - 6 = 5 + 3(-7 + 1)
-13 = 5 + 3(-7 + 1)
-13 = 5 + 3(-6)
-13 = 5 + (-18)
-13 = 5 - 18
-13 = -13
This works!

So the integers are -7 and -6.
7 0
3 years ago
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