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3 years ago

What is the value of z?

Mathematics

1 answer:

zlopas [31]3 years ago

3 0

Answer:

Step-by-step explanation:

The value of the z-score tells you how many standard deviations you are away from the mean. ... A positive z-score indicates the raw score is higher than the mean average. For example, if a z-score is equal to +1, it is 1 standard deviation above the mean. A negative z-score reveals the raw score is below the mean average

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All movies until 4:00 p.m require a discount ticket, and all movies after 4:00 p.m require a regular-price ticket.Each theater a

MrRissso [65]

209 is the answer to you problem hope it helps

8 0

3 years ago

How do I find the domain?

chubhunter [2.5K]

Domain is the set of numbers you can use for the equaiton

remember you can't divide by zero, or take the squaer root of a negtive number (we don't have sqrts in this quesiton so don't worry about last one)

so you can't divide by 0
domain =all real number except those that make divide by zero

where is that?
x-1=0
x=1

when x=1, we can't allw that

domain=all real numbers except 1

7 0

3 years ago

10ac x 6ab x (-2abc) = ?

blsea [12.9K]

Answer:

= -120a³b²c²

Step-by-step explanation:

10ac * 6ab * -2abc

10*6*-2 = -120

ac * ab * abc = a*a*a *b*b*c*c = a³b²c²

then:

10ac * 6ab * -2abc = -120* a³b²c²

= -120a³b²c²

3 0

4 years ago

0.003 convert to fraction

zlopas [31]

Answer: Its 3/1000

Step-by-step explanation:

Put 0.003 over 1 0.003/1 x 1000/1000 = 3/1000

5 0

4 years ago

Read 2 more answers

Combine into a single logarithm.<br><br> 3log(x+y)+2log(x-y)-log(x^2 +y^2)

seropon [69]

Answer:

$3\log _{10}\left(x+y\right)+2\log _{10}\left(x-y\right)-\log _{10}\left(x^2+y^2\right)=\log _{10}\left(\frac{\left(x+y\right)^3\left(x-y\right)^2}{x^2+y^2}\right)$

Step-by-step explanation:

Given the expression

$3log\left(x+y\right)+2log\left(x-y\right)-log\left(x^2\:+y^2\right)$

solving to write into a single logarithm

$3log\left(x+y\right)+2log\left(x-y\right)-log\left(x^2\:+y^2\right)$

$\mathrm{Apply\:log\:rule}:\quad \:a\log _c\left(b\right)=\log _c\left(b^a\right)$

$3\log _{10}\left(x+y\right)=\log _{10}\left(\left(x+y\right)^3\right)$

$=\log _{10}\left(\left(x+y\right)^3\right)+2\log _{10}\left(x-y\right)-\log _{10}\left(x^2+y^2\right)$

$\mathrm{Apply\:log\:rule}:\quad \:a\log _c\left(b\right)=\log _c\left(b^a\right)$

$2\log _{10}\left(x-y\right)=\log _{10}\left(\left(x-y\right)^2\right)$

$=\log _{10}\left(\left(x+y\right)^3\right)+\log _{10}\left(\left(x-y\right)^2\right)-\log _{10}\left(x^2+y^2\right)$

$\mathrm{Apply\:log\:rule}:\quad \log _c\left(a\right)+\log _c\left(b\right)=\log _c\left(ab\right)$

$\log _{10}\left(\left(x+y\right)^3\right)+\log _{10}\left(\left(x-y\right)^2\right)=\log _{10}\left(\left(x+y\right)^3\left(x-y\right)^2\right)$

$=\log _{10}\left(\left(x+y\right)^3\left(x-y\right)^2\right)-\log _{10}\left(x^2+y^2\right)$

$\mathrm{Apply\:log\:rule}:\quad \log _c\left(a\right)-\log _c\left(b\right)=\log _c\left(\frac{a}{b}\right)$

$\log _{10}\left(\left(x+y\right)^3\left(x-y\right)^2\right)-\log _{10}\left(x^2+y^2\right)=\log _{10}\left(\frac{\left(x+y\right)^3\left(x-y\right)^2}{x^2+y^2}\right)$

$=\log _{10}\left(\frac{\left(x+y\right)^3\left(x-y\right)^2}{x^2+y^2}\right)$

Thus,

$3\log _{10}\left(x+y\right)+2\log _{10}\left(x-y\right)-\log _{10}\left(x^2+y^2\right)=\log _{10}\left(\frac{\left(x+y\right)^3\left(x-y\right)^2}{x^2+y^2}\right)$

6 0

3 years ago