Answer:
g^5h^2
Step-by-step explanation:
12g^5h^4, g^5h^2
This is one way of doing it. Break down every number and every variable into a product of the simplest factors. Then see how many of each factor appear in both monomials.
12g^5h^4 = 2 * 2 * 3 * g * g * g * g * g * h * h * h * h
g^5h^2 = g * g * g * g * g * h * h
So far you see every single prime factor of each monomial.
Now I will mark the ones that are present in both. Those are the common factors.
12g^5h^4 = 2 * 2 * 3 * g * g * g * g * g * h * h * h * h
g^5h^2 = g * g * g * g * g * h * h
The greatest common factor is the product of all the factors that appear in both monomials.
GCF = g * g * g * g * g * h * h = g^5h^2
210/20=10.5 per hour
So
2000/10.5=190 hours
Answer:
Step-by-step explanation:
See the solution process below:
Explanation:
The slope-intercept form of a linear equation is: y =mx+b
Where m is the slope and b
is the y-intercept value.
We are given the slope in the problem so we can substitute
−5/6 for m in the formula.
And,
(0,6)
is the y-intercept so we can substitute
6
for
b
in the formula giving:
y
=
−
5
6
x
+
6
The teacher would need 40 centimeters of tape to hang 10 student projects.
Step-by-step explanation:
Given,
Tape used to hang projects = 36 centimeters
Number of projects hanged = 9
We will find unit rate;
9 projects = 36 centimeters
1 project = 
1 project = 4 centimeters
Therefore,
Tape needed to hang 10 projects = 4*10 = 40 centimeters
The teacher would need 40 centimeters of tape to hang 10 student projects.
Keywords: unit rate, multiplication
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