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vodomira [7]
3 years ago
11

What is the slope intercept equation of the line below?

Mathematics
1 answer:
valentina_108 [34]3 years ago
6 0
The answer is letter D
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Using the image, find the distance between the points given on the graph.
Yuliya22 [10]

Answer:

3 units

Step-by-step explanation:

using the distance formula

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Simplify the following expression:<br> 4x - 3y + 2z - 3x - y + 3z = ?
nordsb [41]
Add all the like terms together so 4x-3x is x or 1x -3y-y is -4y 2z+3z is 5z so put them all together it's x-4y+5z
7 0
3 years ago
Help! What's the slope?
Sliva [168]

Answer:

2/7

Step-by-step explanation:

You do the number it goes up, 1 to 3 in this case, over the number it goes sideways, 3 to -4. My teacher always said rise over run to help us remember.

7 0
3 years ago
Please help, I am super stuck and I cant lose points<br><br> this homework is 16 points total
bekas [8.4K]
Hello,

7)  A∪C={1,2,3,4,5,7,9}

8) A∩B={2,4}

C'= complement of C ={2,4,6}

9) A∪B∩C'={1,2,3,4,6,8}∩{2,4,6}={2,4,6}

10) A∪(B∩C')={1,2,3,4}∩{2,4,6}={1,2,3,4,6}

Are you blind?
4 0
3 years ago
If the mean weight of 4 backfield members on the football team is 221 lb and the mean weight of the 7 other players is 202 lb, w
MatroZZZ [7]

Let x_1, x_2, x_3, x_4, x_5, x_6, x_7, x_8, x_9, x_{10}, x_{11} be the weight of i-th player.

1. If the mean weight of 4 backfield members on the football team is 221 lb, then

\dfrac{x_1+x_2+x_3+x_4}{4}=221\ lb.

2. If the mean weight of the 7 other players is 202 lb, then

\dfrac{x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}}{7}=202\ lb.

3. From the previous statements you have that

x_1+x_2+x_3+x_4=221\cdot 4=884 \lb,\\ \\x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}=202\cdot 7=1414\ lb.

Add these two equalities and then divide by 11:

x_1+x_2+x_3+x_4+x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}=884+1414=2298\ lb,\\ \\\dfrac{x_1+x_2+x_3+x_4+x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}}{11}=\dfrac{2298}{11}=208\dfrac{10}{11}\ lb.

Answer: the mean weight of the 11-person team is 208\dfrac{10}{11}\ lb.

4 0
3 years ago
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