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vodomira [7]
2 years ago
11

What is the slope intercept equation of the line below?

Mathematics
1 answer:
valentina_108 [34]2 years ago
6 0
The answer is letter D
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Please someone help asap
dem82 [27]
The right answer is 4 hoped i helped

5 0
3 years ago
6, 8, 11, 12, 2x – 8, 2x + 10, 35, 41, 42, 50
krok68 [10]

Answer:

12

Step-by-step explanation:

(2x-8+2x+10)/2 = 25

(4x+2) = 2×25

4x+2 = 50

4x = 50-2

4x = 48

x = 48/4

x = 12

6 0
3 years ago
Read 2 more answers
Por favor que alguien me ayude con
Contact [7]

Este es el brainly ingles, no hables en español

(4/7).(-3/5) = (4.(-3))/(7.5) = -12/35

(3/5).(-6/7).(-4) = (3.(-6).(-4))/(5.7) = 72/35

6/(1/8) = 6.8 = 48

8 0
4 years ago
Find two consecutive odd numbers such that the sum of three-sevenths of the first number and one-third of the second number is e
ch4aika [34]
I think the answer is 29 and 31

4 0
3 years ago
Read 2 more answers
Last year, Keiko had $20,000 to invest. She invested some of it in an account that paid %7 simple interest per year, and she inv
erma4kov [3.2K]

Answer:

P_2 = \$6,000\\P_1 = \$14,000

Step-by-step explanation:

The formula of simple interest is:

I = P_0rt

Where I is the interest earned after t years

r is the interest rate

P_0 is the initial amount

We know that the investment was $20,000 in two accounts

_______________________________________________

<u><em>For the first account</em></u> r = 0.07 per year.

Then the formula is:

I_1 = P_1r_1t

Where

P_1 is the initial amount in account 1 at a rate r_1 during t = 1 year

I_1 = P_1(0.07)(1)\\\\I_1 = 0.07P_1

<u><em>For the second account </em></u>r = 0.05 per year.

Then the formula is:

I_2 = P_2r_2t

Where

P_2 is the initial amount in account 2 at a rate r_2 during t = 1 year

Then

I_2 = P_2(0.05)(1)\\\\I_2 = 0.05P_2

We know that the final profit was I $1,280.

So

I = I_1 + I_2=1,280

Substituting the values I_1, I_2 and I we have:

1,280 = 0.07P_1 + 0.05P_2

As the total amount that was invested was $20,000 then

P_0 = P_1 + P_2 = 20,000

Then we multiply the second equation by -0.07 and add it to the first equation:

0.07P_1 + 0.05P_2 = 1.280\\.\ \ \ \ \ \ \ \ +\\-0.07P_1 -0.07P_2 = -1400\\-------------

-0.02P_2 = -120\\\\P_2 = 6,000

Then P_1 = 14,000

4 0
3 years ago
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