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2 years ago

If anyone can help me out I would truly appreciate it Please show me step by step

Mathematics

1 answer:

wel2 years ago

3 0

Answer:

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Step-by-step explanation:

Step 1: Define

Identify

0.3y + y/z

y = 10

z = 5

Step 2: Evaluate

Substitute in variables: 0.3(10) + 10/5
Multiply: 3 + 10/5
Divide: 3 + 2
Add: 5

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Scale : 1 cm = 2.5 ft

1 cm = 2.5 ft
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Answer: 3.93 ft

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3 years ago

Write a quadratic function in standard form with a leading coefficient of 1 for the given set of zeros. 7 and 4

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We are given : Zeros x=7 and x=4 and leading coefficent 1.

In order to find the quadratic function in standard form, we need to find the factors of quadratic function first and the multiply by given leading coefficent.

For the given zeros x=7 and x=4, we get the factors (x-7) and (x-4).

So, we need to multiply (x-7) and (x-4) by foil method.

We get

(x-7)(x-4) = x*x + x* -4 -7*x -7*-4

x^2 -4x -7x +28.

Combining like terms, we get

-4x-7x = -11x

x^2 -4x -7x +28 = x^2 -11x +28.

Now, we need to multiply x^2 -11x +28 quadratic by leading coefficent 1.

We get

1(x^2 -11x +28) = x^2 -11x +28.

Therefore, the required quadratic function in standard form is x^2 -11x +28.

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3 years ago

What is nine times for a total loss of 15 3/4 yards

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7 0

3 years ago

Is 8 ,5,1 and -4 an arithmetic sequence.

kolbaska11 [484]

Answer:

The sequence is not geometric or arithmetic because there is no common difference or common ratio between each term.

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3 years ago

Determine if Ginny factored correctly. If not, explain where she made an error. Ginny made a mistake in step 1 when she identifi

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Quadratic equations are second-order equations. Ginney made a mistake when she identified b = 31. It should be b = –31.

<h3>What is a Quadratic Equation?</h3>

A quadratic equation is an equation that can be written in the form of

ax²+bx+c.

Where a is the leading coefficient, and

c is the constant.

In order to find the mistake that Ginny made, we will first find the factors ourselves, therefore, we will factorize the trinomial,

$6x^2 - 31x -30 = 0$

As we can see that the value of constants are,

a = 6

b = -31

c = 30

$6x^2 - 31x -30 = 0\\\\6x^2 - 36x+5x -30 = 0\\\\6x(x-6)+5(x-6)=0\\\\(6x+5)(x-6)=0$

Therefore, the factors of the trinomial $6x^2 - 31x -30 = 0$ are (6x+5) and (x-6).

If we compare our process with Ginny's process, we will find that she has taken the value of the constant b as 31 which is wrong.

Hence, Ginney made a mistake when she identified b = 31. It should be b = –31.

Learn more about Quadratic Equation:

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3 0

2 years ago

Read 2 more answers