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Pepsi [2]
3 years ago
11

g A closed-end manometer was attached to a vessel containing argon. The difference in the mercury levels in the two arms of the

manometer was 9.60 cm. Atmospheric pressure was 783 mm Hg. The pressure of the argon in the container was ________ mm Hg. Selected Answer: Incorrect 773 Answers: 882 793 661 773 Correct 96.0
Chemistry
1 answer:
ElenaW [278]3 years ago
7 0

Answer:

Answer: 882mmHg

Explanation:

In a closed-end manometer, the gas added is under a pressure that is measured against atmospheric pressure. The difference in pressure between both gases is equal to the difference in mercury levels. Thus, the pressure of the argon can be:

783 mmHg - 96.0mmHg = 687mmHg

783 mmHg - 96.0mmHg = 879mmHg

Based on the options, the possible answer (The nearest to the second value) is:

<h3>Answer: 882mmHg</h3>

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1. Coal gasification consists of the chemical transformation of solid coal into gas. The heating values of coal differ, but the
creativ13 [48]

Complete question:

Coal gasification consists of the chemical transformation of solid coal into gas. The heating values of coal differ, but the higher the heating value, the higher the value of the gas produced (which is essentially methane, carbon monoxide, hydrogen, etc.). The following coal has a reported heating value of 29,770 KJ/Kg as received. Assuming that this is the gross heating value, calculate the net heating value.. Component__________Percent  C___________________71

H2__________________5.6

N2__________________1.6

S____________________2.7

Ash__________________6.1

O2___________________13

Answer:

LHV = 28478.8 KJ/kg

Explanation:

The gross heating value is also the higher heating value (HHV), while the net heating value is the lower heating value (LHV).

This involves the conversion from higher heating value (HHV) to lower heating value(LHV).

Let's use the formula:

LHV = HHV - 0.212H - 0.0245M - 0.008A

We are given

HHV = 29,770 KJ/kg = 29.770MJ/kg

H = hydrogen% =5.6%

A = oxygen% = 13%

M = 0

Substituting the figures in the formula, we have:

LHV = 29.770 - 0.212*5.6 - 0.0245*0 - 0.008*13

= 29.770 - 1.1872 - 0 - 0.104

= 28.4788 MJ/kg

= 28478.8 KJ/kg

LHV = 28478.8 KJ/kg

The net heating value, LHV = 28478.8 KJ/kg

3 0
3 years ago
Need help with 22 and 24<br>​
choli [55]

Answer:

22:

Formular:

atomic \: mass =  \frac{ \sum(isotopic \: mass \times \%abundance)}{100}  \\

substitute:

atomic \: mass =  \frac{(23.985 \times 78.70) + (24.986 \times 10.13) + (25.983 \times 11.17)}{100}  \\  \\  =  \frac{(1887.620) + (253.108) + (290.230)}{100}  \\  \\  =  \frac{2430.958}{100}  \\  \\ { \boxed{ \boxed{average \: atomic \: mass = 24.3 \: amu}}}

23:

<em>Same</em><em> </em><em>element</em><em> </em><em>is</em><em> </em><em>represented</em><em> </em><em>by</em><em> </em><em>same</em><em> </em><em>number</em><em> </em><em>of</em><em> </em><em>protons</em><em>.</em><em> </em>

Answer:

6 protons. 6 protons

7 neutrons. 8 neutrons

6 electrons. 6 electrons

Note: <u>Atoms</u><u> </u><u>with</u><u> </u><u>same</u><u> </u><u>proton</u><u> </u><u>number</u><u> </u><u>but</u><u> </u><u>different</u><u> </u><u>mass</u><u> </u><u>number</u><u> </u><u>are</u><u> </u><u>called</u><u> </u><u>isotopes</u>

5 0
3 years ago
Read 2 more answers
Formula for Tricarbon heptabromide.
DiKsa [7]
I believe it would be Au^4Cl8
7 0
3 years ago
Wind patterns choose all that apply
kumpel [21]
I think the answer is B.
4 0
3 years ago
Which of the following is an example of a change of state?
lord [1]

Answer:

Option B

Explanation:

  • For Option A the state is not changing but just has different look now.
  • For Option B the state is changing from gas to liquid drops due to cold glass
  • For Option C it hasn't changed state as both corn and flower is solid
  • For Option D paper and ash are both solids

Therefore our answer must be Option B

6 0
2 years ago
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