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Zielflug [23.3K]
2 years ago
8

Calculate the density of an aluminum block with a volume of 100 cm3 and a mass of 270g.

Chemistry
1 answer:
m_a_m_a [10]2 years ago
6 0

Answer:

<h2>2.7 g/cm³</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume}  \\

From the question we have

density =  \frac{270}{100}  =  \frac{27}{10} \\

We have the final answer as

<h3>2.7 g/cm³</h3>

Hope this helps you

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An unknown quantity of sugar was completely dissolved in water at 75 degrees Celsius to form a clear and colorless solution. The
Nataly_w [17]

Answer:

67

Explanation:

5 0
3 years ago
Plz help!!! This is timed!!!
pogonyaev
58.7 %

Please correct me if I’m wrong. :)
7 0
2 years ago
An atom has the following electron configuration 1s2 2s2 2p6 3s2 3p4 . How many valence electrons does this Atom have
yawa3891 [41]

Answer:

6

Explanation:

This atom is sulfur (if the electrons are equal to the protons/not an ion). You can tell the number of valence electrons by looking at the individual shell. The first shell (1s) can only hold 2 electrons. The second shell (2s and 2p) can hold 8 electrons. The third shell (3s and 3p), which is the valence shell, only has 6 out of its possible 8 electrons, so this atom has 6 valence electrons.

6 0
3 years ago
If the H+ in a solution is 1x10^-1 mol/L what is the OH-
damaskus [11]
PH scale is used to determine how acidic or basic a solution is.
we have been given the hydrogen ion concentration. Using this we can calculate pH,
pH = - log[H⁺]
pH = - log (1 x 10⁻¹ M)
pH = 1
using pH can calculate pOH
pH + pOH = 14
pOH = 14 - 1
pOH = 13
using pOH we can calculate the hydroxide ion concentration 
pOH = - log [OH⁻] 
[OH⁻] = antilog(-pOH)
[OH⁻] = 10⁻¹³ M
hydroxide ion concentration is 10⁻¹³ M
8 0
3 years ago
What is the empirical formula of a vanadium (i) oxide given that 20.38 grams of vanadium combines with oxygen to form 23.58 gram
oksano4ka [1.4K]

V₂O is the empirical formula of a vanadium (i) oxide given that 20.38 grams of vanadium combines with oxygen to form 23.58 grams of the oxide.

The simplest whole number ratio of the atoms of the elements in a specific compound is shown by the empirical formula for that compound. When the mass of each component of a compound or its % composition by mass is known, an empirical formula may typically be computed.

% composition is equal to (mass of an element minus mass of the compound) / 100%.

Given

Vanadium weighs 20.38 g.

The oxide's mass is 23.58 g.

% Vanadium composition: (20.38 g/23.58 g) 100%

= 86.43%

Oxygen mass equals 23.58 g minus 20.38 g

= 3.2 g

100% of oxygen's composition is (3.2/g/23.58 g)

= 13.57%

Atomic mass and number are related by composition percentage.

Vanadium's atomic weight is 50.94 g/mol.

Atomic weight of V = 86.43 / 50.94

= 1.6967

Oxygen has an atomic mass of 16 g/mol.

O atom count is 13.57/16.

= 0.8481

Now on calculation the ratio of Vanadium to the oxygen is

1.6967/0.8481 = 2/1

Ratio of whole numbers is 2:1

Thus V₂O is the empirical formula .

Learn more about empirical formula here brainly.com/question/13058832

#SPJ4

6 0
1 year ago
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