Answer:
A. One unpaired electron
B. 5 unpaired electrons
Explanation:
In A ,Fe is in +3 oxidation state and Electronic configuration- [Ar]3d5
And NO2 is a strong field ligand hence it causes pairing in t2g orbitals and results one unpaired electron in dZX orbital.
In B, also Fe is in +3 oxidation state but F is weak field ligand hence causes no pairing of Electrons hence it results 5 unpaired electrons with electronic configuration t2g^3 eg^2
Answer:here is the answer
Scholarcy, the online article summarizer tool, reads your research articles, reports and book chapters in seconds and breaks them down into bite-sized sections – so you can quickly assess how important any document is to your work.
Explanation:
Mixture between a liquid and particles of a solid
The law of conservation of mass states that the mass of a system must remain constant everytime, it can neither be created or destroyed. This means the number of atoms of each element on reactant side must equal the number of atoms of each element on product side.
First we figure out the chemical formula for each compound by taking advantage of oxidation states which are able to tell us whether an element will lose or gain an electron
Strontium hydroxide?
Sr is an alkaline earth metal which has 2 valence electrons that when both are lost it has an oxidation state of +2. Since we know the hydroxide ion has a charge of -1,
, Then two
are needed to form compound, hence we have 
zirconium (I) perchlorate?
The oxidation state of zirconium is +1 since it is stated that we have zirconium(I). Converserly, perchlorate has a -1 charge which further proves that zirconium has a +1 oxidation state
The product would have a strontium diperchlorate because we know from earlier that Sr has a +2 oxidation state, and we would also have ZrOH because Zr has a +1 oxidation state and
has a -1 charge
The unbalanced equation with all chemicals formulas would be

Using the law of conservation of mass, it is clear that there is 1 molecule of
on reactant side as compared to 2 molecules of
on product side. On the other hand, the are 2 molecules of
on reactant side and 1 molecule of
on product side. To balance we add a coefficient of 2 on
and a coefficient of 2 on ZrOH,
.
Is there any multiple choices?