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4vir4ik [10]
4 years ago
12

If equal moles of acid and base react in a neutralization reaction, they cancel out many of each other's properties.

Chemistry
1 answer:
anyanavicka [17]4 years ago
4 0
<span>1. If equal moles of acid and base react in a neutralization reaction, they cancel out many of each other's properties.

Answer is True.

2. 
</span><span>A neutral salt is formed by which type of reaction?

Answer is B.

3. </span><span>Which could be the original acid and base that react to produce the salt KCl?

Answer is A.

4. 
</span><span>Net ionic equations for strong acid-strong base reactions are always: H+ (aq) + OH−(aq Imported Asset H2O (l).

Answer is True.

5. 
</span><span>Which net ionic equation best represents a weak acid-strong base reaction?
Answer is A.

6. 
</span><span>The equation, H2SO4 (aq) + Sr(OH)2 (aq) Imported Asset SrSO4 (aq) + H2O (l), represents:

Answer is B.

7. 
</span><span>When choosing which indicator to use in a titration reaction, you should consider:

Answer is </span><span>the relative strengths of the acid and base you are using in the titration
</span><span>
8. 
</span><span>When a small amount of acid is added to a buffer, the weak base form of the buffer is converted to:

Answer is C.

9. 
</span><span>Buffers are systems that resist changes in pH by converting strong acids or bases to weak acids or bases.

Answer is True.</span>
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Determine the number of unpaired electrons expected for [Fe(NO2)6]3−and for [FeF6]3− in terms of crystal field theory.
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Answer:

A. One unpaired electron

B. 5 unpaired electrons

Explanation:

In A ,Fe is in +3 oxidation state and Electronic configuration- [Ar]3d5

And NO2 is a strong field ligand hence it causes pairing in t2g orbitals and results one unpaired electron in dZX orbital.

In B, also Fe is in +3 oxidation state but F is weak field ligand hence causes no pairing of Electrons hence it results 5 unpaired electrons with electronic configuration t2g^3 eg^2

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How do you write the balanced equation for strontium hydroxide and zirconium (I) perchlorate
Andrei [34K]

The law of conservation of mass states that the mass of a system must remain constant everytime, it can neither be created or destroyed. This means the number of atoms of each element on reactant side must equal the number of atoms of each element on product side.

First we figure out the chemical formula for each compound by taking advantage of oxidation states which are able to tell us whether an element will lose or gain an electron

Strontium hydroxide?

Sr is an alkaline earth metal which has 2 valence electrons that when both are lost it has an oxidation state of +2. Since we know the hydroxide ion has a charge of -1, -_{OH}, Then two -_{OH} are needed to form compound, hence we have SrOH_2

zirconium (I) perchlorate?

The oxidation state of zirconium is +1 since it is stated that we have zirconium(I). Converserly, perchlorate has a -1 charge which further proves that zirconium has a +1 oxidation state

The product would have a strontium diperchlorate because we know from earlier that Sr has a +2 oxidation state, and we would also have ZrOH because Zr has a +1 oxidation state and -_{OH} has a -1 charge

The unbalanced equation with all chemicals formulas would be

SrOH_2_(s) + ZrClO^{-} _4(aq) ==> Sr(ClO^{-} _4)_2(aq) + ZrOH(aq)

Using the law of conservation of mass, it is clear that there is 1 molecule of ClO^{-} _4 on reactant side as compared to 2 molecules of ClO^{-} _4 on product side. On the other hand, the are 2 molecules of -_{OH} on reactant side and 1 molecule of  -_{OH} on product side. To balance we add a coefficient of 2 on ZrClO_4 and a coefficient of 2 on ZrOH,

SrOH_2_(s) + 2ZrClO_4_(aq) ==> Sr(ClO_4)_2_(aq) + 2ZrOH(aq).

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