Answer:
0.95
Step-by-step explanation:
19/20 as a decimal is 0.95
Answer:
The 80% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.149, 0.207).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of 
, and a confidence level of 
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of 
.
Suppose a sample of 292 tenth graders is drawn. Of the students sampled, 240 read above the eighth grade level.
So 292 - 240 = 52 read below or at eight grade level, and that 
80% confidence level
So 
, z is the value of Z that has a pvalue of 
, so 
.
The lower limit of this interval is:
The upper limit of this interval is:
The 80% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.149, 0.207).
Answer:
B
Step-by-step explanation:
B-X=A
or
B-A=X
or
X=B-A
![X=\left[\begin{array}{ccc}-5&-1&6\\4&1&2\\0&-3&2\end{array}\right] -\left[\begin{array}{ccc}-1&-2&3\\4&8&-6\\0&1&5\end{array}\right] \\=\left[\begin{array}{ccc}-5+1&-1+2&6-3\\4-4&1-8&2+6\\0-0&-3-1&2-5\end{array}\right] \\=\left[\begin{array}{ccc}-4&1&3\\0&-7&8\\0&-4&-3\end{array}\right]](https://tex.z-dn.net/?f=X%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-5%26-1%266%5C%5C4%261%262%5C%5C0%26-3%262%5Cend%7Barray%7D%5Cright%5D%20-%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-1%26-2%263%5C%5C4%268%26-6%5C%5C0%261%265%5Cend%7Barray%7D%5Cright%5D%20%5C%5C%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-5%2B1%26-1%2B2%266-3%5C%5C4-4%261-8%262%2B6%5C%5C0-0%26-3-1%262-5%5Cend%7Barray%7D%5Cright%5D%20%5C%5C%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-4%261%263%5C%5C0%26-7%268%5C%5C0%26-4%26-3%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
so correct answer is a7 as
Answer:
1721 $
1612.80
Step-by-step explanation:
Straight line depreciation means depreciation is the same spread over for all the years. The spread over amount is nothing but total cost of equipment - salvage value.
Here we have
Cost of equipment(Purchase cost) ... 18000
Shipping costs ... 620
Installation costs ... 590
Total cost of equipment ... 19210
Less: salvage value at the end ... 2000
Net cost of equipment for 10 years ... 17210
Depreciation per year = Net cost /number of years of life
= 17210/10 = 1721/-
Hence answer is 1721/- for all years and also hence for year 2.
--------------------
Peach tree has an average life of 12 years. First 3 years no benefit would arise, 4 to 8 would be peak and after that slowly decreasing.
Hence in 9th year there would be least value and least depreciation.
Hence answer is $1612.80
