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3 years ago

Solve the equation 4-t=3(t-1)-5

Mathematics

2 answers:

SSSSS [86.1K]3 years ago

8 0

Answer:

t = 3

Step-by-step explanation:

$4 - t = 3(t - 1) - 5$

$4 - t = 3t - 3 - 5$

$4 - t = 3t - 8$

$- t - 3t = - 8 - 4$

$- 4t = - 12$

$t = 3$

STALIN [3.7K]3 years ago

5 0

Answer:

t=3

Step-by-step explanation:

4-t=3t-3-5

4-t=3t-8

4=4t-8

12=4t/4

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Option C

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<h3><u>Solution:</u></h3>

Let there are two cylinder of heights "h" and "H"

Also radius to be "r" and "R"

$\text { Volume of a cylinder }=\pi r^{2} h$

Where π = 3.14 , r is the radius and h is the height

Now the ratio of their heights and radii is 2:3 .i.e

$\frac{\mathrm{r}}{R}=\frac{\mathrm{h}}{H}=\frac{2}{3}$

<em><u>Ratio for the volumes of two cylinders</u></em>

$\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\frac{\pi r^{2} h}{\pi R^{2} H}$

Cancelling the common terms, we get

$\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\left(\frac{\mathrm{r}}{R}\right)^{2} \times\left(\frac{\mathrm{h}}{\mathrm{H}}\right)$

Substituting we get,

$\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\left(\frac{2}{3}\right)^{2} \times\left(\frac{2}{3}\right)$

$\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\frac{2 \times 2 \times 2}{3 \times 3 \times 3}$

$\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\frac{8}{27}$

Hence, the ratio of volume of two cylinders is 8 : 27

7 0

3 years ago

NEED ANSWER FAST PLASE FAST

Dovator [93]

Answer:

D. no solution

Step-by-step explanation:

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put in the second equation

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