Please help! This is Algebra 1, and i’m like so confused...

Solve the following system of equations y=2x+10. y=3x+12

igor_vitrenko [27]

Answer:

1. Slope: 2 y-intercept: (0,−10)

2. Slope: 3 y-intercept: (0,12)

Step-by-step explanation:

3 0

3 years ago

Han has Spent 75 minutes practicing the piano over the weekend priya practice the violin for 152% as much time as hand practicin

madam [21]

Answer: 114 minutes

Step-by-step explanation:

From the question, we are informed that Han has Spent 75 minutes practicing the piano over the weekend while Priya practice the violin for 152% as much time as Han used in practicing the piano.

Therefore, the number of minutes used in practicing by Priya would be gotten by multiplying 152% by 75 minutes. This would be:

= 152% × 75 minutes.

= 152/100 × 75minutes

= 1.52 × 75 minutes

= 114 minutes

5 0

3 years ago

Is the relation {(1, 3), (-4, 0), (3, 1), (0,4), (2, 3)} a function? Why or why not?

gavmur [86]

Answer:

Yes.

The relation is a function because every element in the domain (the x's) is mapped to one element in the range (the y's).

Step-by-step explanation:

For a relation that is a set of points all you have to look for while igorning any duplicate points is that all of the x's are different. If there are any 2 (or more) x's that are the same, then it is not a function.

So there are no duplicate points.

For example the set {(1,5),(2,5)(1,5)} is really just {(1,5),(2,5)}.

Anyways the x's in the points are (in order from left to right):

1

-4

3

0

2

All of these are different, I did not list a value for x that was same anywhere in that list. So it is a function.

The relation is a function because there is no x that gets mapped to more than one y.

6 0

3 years ago

Find the coefficient of the squared term in the simplified form for the second derivative, f "(x) for f(x) = (x3 + 2x + 3)(3x3 −

diamong [38]

$Use:\\(h(x)\cdot g(x))'=h'(x)g(x)+h(x)g'(x)\\\\h(x)=x^3+2x+3\to h'(x)=3x^2+2\\\\g(x)=3x^3-6x^2-8x+1\to g'(x)=9x^2-12x-8\\\\f(x)=(x^3+2x+3)(3x^3-6x^2-8x+1)\\\\f'(x)=(x^3+2x+3)'(3x^3-6x^2-8x+1)+(x^3+2x+3)(3x^3-6x^2-8x+1)'\\\\=(3x^2+2)(3x^3-6x^2-8x+1)+(x^3+2x+3)(9x^2-12x-8)\\\\=9x^5-18x^4-24x^3+3x^2+6x^3-12x^2-16x+2+9x^5-12x^4-8x^3+18x^3-24x^2-16x+27x^2-36x-24\\\\=18x^5-30x^4-8x^3-6x^2-68x-22$

$f''(x)=(18x^5-30x^4-8x^3-6x^2-68x-22)'\\\\=90x^4-120x^3-24x^2-12x-68\\\\Answer:\ \boxed{-24}$

7 0

3 years ago

Read 2 more answers

An organisation buys a truck on hire purchase The cost is 500000 The contract states a deposit or 35% and 12 annual payments of

Mama L [17]

Answer:

total finance cost is 274064

interest in 5 year = 17568.21

creditors reduced in year 8 is 21812.87

Step-by-step explanation:

given data

cost = 500000

rate 35%

installment = 12

annual payment = 49922

to find out

the total finance cost and interest is charged in 5 year and creditors reduced in year 8

solution

we know cost is 500000 so down payment will be

payment = 35% of 500000 = 35/100 × 500000

so payment = 175000

and 12 installment purchase price is 12 × 49922

purchase price = 599064

so total finance cost is payment + purchase price - cost

finance cost = 175000 + 599064 - 500000

so total finance cost is 274064

and

we know in 1 to 12 digit sum is 78

so interest in 5 year

interest = 5/78 of total finance cost

interest = 5/78 × 274064

interest in 5 year = 17568.21

and

interest in 8 year

interest = 8/78 of total finance cost

interest = 8/78 × 274064

interest in 8 year = 28109.13

so

creditors reduced in year 8 = 49922- 28109.13

creditors reduced in year 8 is 21812.87

4 0

3 years ago