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professor190 [17]
3 years ago
6

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Computers and Technology
1 answer:
weeeeeb [17]3 years ago
4 0

Answer:

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Which key removes all data from an active cell with one click? A. Esc B. Delete C. Tab D. F2
bija089 [108]
The answer is B. Delete
6 0
3 years ago
Read 2 more answers
Which of the following statements is false? a. Classes (and their objects) encapsulate, i.e., encase, their attributes and metho
prohojiy [21]

Answer:

The correct option is C: For objects to communicate effectively with one another, each must know how the other object is implemented.

Explanation:

For effective communication of objects with each other, there is no need for each object to know how the other object is implemented. The rules for communication are already defined, and hence you do not have to know, as details of implementation are hidden. Hence the only false statement from the options is C.

5 0
3 years ago
Shania has started a new job as an app developer. Her first task was to make an old app designed for Android available on other
Fantom [35]

Answer:

B. Use cross-platform tools to write code that will translate the existing Android app code into different native formats.

Explanation:

Cross-platform application development tools are tools that can be used tool generate applications of different platforms, by just writing a single type of code. It has the ability to automatically create an application of a different platform from another.

A developer can develop an application like Android and convert it to IOS for Apple. Xamarin, Appcelerator coroner etc, are all examples of cross-platform tools.

8 0
3 years ago
Assume a TCP sender is continuously sending 1,090-byte segments. If a TCP receiver advertises a window size of 5,718 bytes, and
Arturiano [62]

Answer:

for the 5 segments, the utilization is 3.8%

Explanation:

Given the data in the question;

segment size = 1090 bytes

Receiver window size = 5,718 bytes

Link transmission rate or Bandwidth = 26 Mbps = 26 × 10⁶ bps

propagation delay = 22.1 ms

so,

Round trip time = 2 × propagation delay = 2 × 22.1 ms = 44.2 ms

we determine the total segments;

Total segments = Receiver window size / sender segment or segment size

we substitute

Total segments = 5718 bytes / 1090 bytes

Total segments = 5.24587 ≈ 5

Next is the throughput

Throughput = Segment / Round trip

Throughput = 1090 bytes / 44.2 ms

1byte = 8 bits and 1ms = 10⁻³ s

Throughput = ( 1090 × 8 )bits / ( 44.2 × 10⁻³ )s

Throughput = 8720 bits / ( 44.2 × 10⁻³ s )

Throughput = 197.285 × 10³ bps

Now Utilization will be;

Utilization = Throughput / Bandwidth

we substitute

Utilization = ( 197.285 × 10³ bps ) / ( 26 × 10⁶ bps )

Utilization = 0.0076

Utilization is percentage will be ( 0.0076 × 100)% = 0.76%

∴ Over all utilization for the 5 segments will be;

⇒ 5 × 0.76% = 3.8%

Therefore, for the 5 segments, the utilization is 3.8%

4 0
3 years ago
Easy coding question, please help.
borishaifa [10]

Answers:

What is the index of the last element in the array? stArr1.length()-1

This prints the names in order. How would I print every other value? Change line 4 to: index = index +2

Change line 7 to: i < names.length

5 0
3 years ago
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