Answer:
The Proof for
△ABD ≅ △CBD is below
Step-by-step explanation:
Given:


AD = CD .........BD bisect AC
To Prove:
△ABD ≅ △CBD
Proof:
In ΔABD and ΔCBD
BD ≅ BD ....……….{Reflexive Property}
∠ADB ≅ ∠CDB …………..{Measure of each angle is 90°(
)}
AD ≅ CD ....……….{
}
ΔABD ≅ ΔCBD .......….{By Side-Angle-Side Congruence test} ...Proved
Answer:
9
Explanation:
9 root 2 = root 81 x root 2 = root 162
Root 162 = 12.7279220614
9^2 + b^2 = 12.7279220614^2
81 + b^2 = 162
b^2 = 81
Root both
B = 9
Answer:
D
All the other ones were correct sooo
Answer:
It was in the watwr for 6 seconds and out for 6 seconds
Step-by-step explanation:
Answer and Explanation:
Using trig ratios, we can express the given values of sin u and tan v as shown below
![\begin{gathered} \sin u=\frac{opposite\text{ of angle u}}{\text{hypotenuse}}=\frac{2}{5} \\ \tan v=\frac{opposite\text{ of angle v}}{\text{hypotenuse}}=\sqrt[]{21} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Csin%20u%3D%5Cfrac%7Bopposite%5Ctext%7B%20of%20angle%20u%7D%7D%7B%5Ctext%7Bhypotenuse%7D%7D%3D%5Cfrac%7B2%7D%7B5%7D%20%5C%5C%20%5Ctan%20v%3D%5Cfrac%7Bopposite%5Ctext%7B%20of%20angle%20v%7D%7D%7B%5Ctext%7Bhypotenuse%7D%7D%3D%5Csqrt%5B%5D%7B21%7D%20%5Cend%7Bgathered%7D)
So we can go ahead and label the sides of the triangle as shown below;
We can find the value of u as shown below;

We can find v as shown below;