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Margaret [11]
3 years ago
10

What is the product of complex numbers (-3i +4) and (3i +4)??? please explain

Mathematics
2 answers:
Temka [501]3 years ago
7 0
Product of complex numbers (-3i +4) and (3i +4)

(x - y)(x + y) = x² - y²

(-3i +4)(3i +4) = (4 -3i )(4 + 3i) = 4² - (3i)² = 16 - 9*(-1)=16 + 9 = 25
drek231 [11]3 years ago
6 0

Answer:

(-3i+4)*(3i+4)=25

Step-by-step explanation:

1. First writhe the complex numbers to multiply:

(-3i+4)*(3i+4)

2. Multiply the first term of the first parentheses by the first term of the second parentheses:

-3i*3i=-9i^{2}

3. Multiply the first term of the first parentheses by the second term of the second parentheses:

-3i*4=-12i

4. Multiply the second term of the first parentheses by the first term of the second parentheses:

4*3i=12i

5. Multiply the second term of the first parentheses by the second term of the second parentheses:

4*4=16

6. Write all the terms:

(-3i+4)*(3i+4)=-9i^{2}-12i+12i+16

7. Add up the terms:

(-3i+4)*(3i+4)=-9i^{2}+16

8. As i^{2}=-1:

(-3i+4)*(3i+4)=-9(-1)+16\\(-3i+4)*(3i+4)=9+16\\(-3i+4)*(3i+4)=25

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