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Triss [41]
3 years ago
14

Helpppppppppppppppppppppppppppppppppppppppppppppppppppppppppppp

Mathematics
2 answers:
dlinn [17]3 years ago
8 0

Answer: D since the equation would be y=10x

Step-by-step explanation:

Ghella [55]3 years ago
7 0

Answer:

the answer to the question is d (8,85)

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Sasha is tracking the results of the water balloon contest. She wants to determine how high Maggie’s balloon is when it is direc
arsen [322]

Answer:

Maggie's ballon is 12 high.

Step-by-step explanation:

We are asked to find the y-value, and the x-value is given:

Plug the values in to solve for y.

y = -(2)^2 + 17(2) - 42 y

= -(4) + 34 - 42 y

= -4 + 34 - 42 y

= -12

The negative sign tells the direction. It is negative because the ballon is in the opposite direction.


4 0
4 years ago
A student researcher compares the ages of cars owned by students and cars owned by faculty at a local state college. A sample of
diamong [38]

Answer:

The point estimate for the true difference between the population means is 0.13.

The 90% confidence interval for the difference between the true mean ages for cars owned by students and faculty is between -0.35 years and 0.61 years.

Step-by-step explanation:

To solve this question, before building the confidence interval, we need to understand the central limit theorem and subtraction between normal variables.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Subtraction between normal variables:

When we subtract two normal variables, the mean is the subtraction of the means while the standard deviation is the square root of the sum of the variances.

A sample of 263 cars owned by students had an average age of 7.25 years. The population standard deviation for cars owned by students is 3.77 years.

This means that:

\mu_s = 7.25, \sigma_s = 3.77, n = 263, s_s = \frac{3.77}{\sqrt{263}} = 0.2325

A sample of 291 cars owned by faculty had an average age of 7.12 years. The population standard deviation for cars owned by faculty is 2.99 years.

This means that:

\mu_f = 7.12, \sigma_f = 2.99, n = 291, s_f = \frac{2.99}{\sqrt{291}} = 0.1753

Difference between the true mean ages for cars owned by students and faculty.

Distribution s - f. So

\mu = \mu_s - \mu_f = 7.25 - 7.12 = 0.13

This is also the point estimate for the true difference between the population means.

s = \sqrt{s_s^2+s_f^2} = \sqrt{0.2325^2+0.1753^2} = 0.2912

90% confidence interval for the difference:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.9}{2} = 0.05

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.05 = 0.95, so Z = 1.645.

Now, find the margin of error M as such

M = zs = 1.645*0.2912 = 0.48

The lower end of the interval is the sample mean subtracted by M. So it is 0.13 - 0.48 = -0.35 years

The upper end of the interval is the sample mean added to M. So it is 0.13 + 0.48 = 0.61 years.

The 90% confidence interval for the difference between the true mean ages for cars owned by students and faculty is between -0.35 years and 0.61 years.

5 0
3 years ago
Giving brainlist to whoever answers this question
ratelena [41]

Answer:

thanks :)

Step-by-step explanation:

4 0
3 years ago
if one glass contians 175ml of juice ,determine the maximum number of glasses that can be filled with 10litre​
monitta

Answer:

57 1/7

Step-by-step explanation:

1 glass = 175ml or 0.175litres what about 10litres

6 0
3 years ago
HELP PLZ ASAP ILL MARK U AS BRAINLIEST
Dmitry_Shevchenko [17]
6/4= 1.5

8/4= 2 

As you can see, this is a proportional relationship. 

The scale factor is 4. 

I hope this helps!
~kaikers
6 0
3 years ago
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