Answer:
dog
Explanation:
The python program has four lists, A, B, C, and E which is a list of the first three lists. Lists are unordered indexed data structures, it is accessed by an index starting from 0 to n (which is the length of the list minus one).
The E list is a list of lists with three list items starting from index zero to two. E[0][1] is used to access the item "dog" in the first list item of the E list.
Answer:
a) the average CPI for machine M1 = 1.6
the average CPI for machine M2 = 2.5
b) M1 implementation is faster.
c) the clock cycles required for both processors.52.6*10^6.
Explanation:
(a)
The average CPI for M1 = 0.6 x 1 + 0.3 x 2 + 0.1 x 4
= 1.6
The average CPI for M2 = 0.6 x 2 + 0.3 x 3 + 0.1 x 4
= 2.5
(b)
The average MIPS rate is calculated as: Clock Rate/ averageCPI x 10^6
Given 80MHz = 80 * 10^6
The average MIPS ratings for M1 = 80 x 10^6 / 1.6 x 10^6
= 50
Given 100MHz = 100 * 10^6
The average MIPS ratings for M2 = 100 x 10^6 / 2.5 x 10^6
= 40
c)
Machine M2 has a smaller MIPS rating
Changing instruction set A from 2 to 1
The CPI will be increased to 1.9 (1*.6+3*.3+4*.1)
and hence MIPS Rating will now be (100/1.9)*10^6 = 52.6*10^6.
Answer:
Sam should send a digital document and request a signature. The could be fax or even an image printed out, if neither is possible get in contact with eh owner and his lawyer for more help.
Explanation:
I need some answer chouices but they use iphones
