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NARA [144]
3 years ago
8

You just turned on a four port Ethernet switch (it hasn’t learned any addresses yet) and connected a host to each port. You send

packet #1 from 00:11:22:33:44:55 to 66:77:88:99:00:11 which arrives at port 1 of your switch. Next, packet #2 is sent from 22:33:44:55:66 to 00:11:22:33:44:55 which arrives at port 3 of your switch. Which of the following are true?
1. Packet #1 is broadcast on all ports
2. After the first packet is received, the switch associates 66:77:88:99:00:11 with port 1
3. Packet #2 is only sent out on port 1
4. Packet #2 is sent out on ports 1, 2, 4
Computers and Technology
1 answer:
butalik [34]3 years ago
7 0

Answer:

Option 2 is correct.

Explanation:

When the user recently switched over that port Ethernet device, which is, no addresses have yet been acquired as well as a client has been linked on each port. He sends #1 packet from 00:11:22:33:44:55 to 66:77:88:99:00:11 arriving at the device's port 1. Next packet #2 is transmitted between 22:33:44:55:66 to 00:11:22:33:44:55 that appears at the switch's port 3.

So that the Package # 2 will be sent only through port 1 by the user who switched over the network.

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You are having a problem with your Windows computer that is isolated to a single graphics editing program that you use every day
Murljashka [212]

Answer:

I'm not a big tech head but I know that creating a restore point is highly recommended for changing anything that you aren't 100% sure about to your computer.

8 0
3 years ago
What is the total utilization of a circuit-switched network, accommodating five users with equal bandwidth share, and the follow
Kryger [21]

Answer:

56.6%

Explanation:

Suppose a user is given bandwidth per user = 100

Total number of users = 5

Total bandwidth share for all 5 users = number of users * bandwidth per user = 5 * 100 = 500

So now max bandwidth is 500.

Bandwidth share of 2 persons with 91% per user = 2 X 91 = 182

Bandwidth share of 2 persons with 44% per user = 2 X 44 = 88

Bandwidth share of 1 persons with 13% per user = 1 X 13 = 13

Bandwidth under utilization by 5 users = 182 + 88 + 13 = 283

Total bandwidth utilization in percentage = (bandwidth under usage/maximum bandwidth of the network)*100 = (283/500)*100 = 56.6%

5 0
4 years ago
What is the difference between SNS and SQS?
vampirchik [111]

Answer: (B) SNS is a push notification service, whereas SQS is a message system that requires worker nodes to poll a queue

Explanation:

In SNS the messages are delivered as soon as they are sent however in SQS they are kept in a queue and are delivered upon polling.

8 0
4 years ago
A School is interested in computerizing their students
Dafna1 [17]

Answer:

Explanation:

To execute this program, and check grades accordingly, if..else statement will be used easily.

The pseudo code of this program is given below while flowchart of this program is attached with this solution

StartProgram to Check Grade;

if(grade in rage of 150-100)  

{

   A

}

 else if (grade is in range of 60-74)

 {  

   B

 }

 else if (grade is in range of 50-59)

 {

   C

 }

 else if (grade is in range of 40-49)

 {

  D

 }

else //GRADE IS IN RANGE 0-39

{

 E

}

Stop the program!;

6 0
3 years ago
Attending a small group meeting to learn about heart-healthy recipes is an example of a(n): Group of answer choices mass media c
Dmitriy789 [7]

The correct answer is B) interpersonal communication channel.

Attending a small group meeting to learn about heart-healthy recipes is an example of an interpersonal communication channel.

Here, we are talking about a type of communication process in which the parties involved freely express their opinions, emotions, ideas, and concepts about one of many topics. In this type of communication, nonverbal communication, gestures, and facial expressions are as important as verbal communication. That is why a small meeting like the mentioned above can be considered as an interpersonal communication channel.

4 0
4 years ago
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