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2 years ago

6

Convert 105 base 10 to binary number

2 answers:

Vitek1552 [10]2 years ago

8 0

Decimal 105 to Binary Conversion
The base-10 value of 105^10 is equal to base-2 value of 1101001^2

spayn [35]2 years ago

4 0

The base-10 value of 10510 is equal to base-2 value of 11010012. Brainliest

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Please help !!<br> Solve for x:<br><br> -2<br> -2/3<br> -3/2<br> -3

Kryger [21]

Answer:

x = $\frac{3}{2}$

Step-by-step explanation:

Given 2 intersecting chords, then the product of the parts of one chord is equal to the product of the parts of the other chord, that is

18x = 9 × 3 = 27 ( divide both sides by 18 )

x = $\frac{27}{18}$ = $\frac{3}{2}$

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2 years ago

What percent of 67.5 is 7.02

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Use the proportion equation. Cross multiply. Answer is 10.4%

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3 years ago

What equals 106 multiplication

DerKrebs [107]

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3 years ago

What is the product of all constants $k$ such that the quadratic $x^2 + kx +15$ can be factored in the form $(x+a)(x+b)$, where

Setler79 [48]

Answer:

$k=-16,k=-8,k=8,k=16$

Step-by-step explanation:

We are given quadratic equations as

$x^2+kx+15$

and it can be factored as

$=(x+a)(x+b)$

now, we can multiply factor term

$(x+a)(x+b)=x^2+(a+b)x+ab$

now, we can compare

$x^2+(a+b)x+ab=x^2+kx+15$

so, we get

$k=a+b$

$ab=15$

we are given that

'a' and 'b' are integers

so, we can find all possible factors

$15=(-1\times -15),(1\times 15)$

$15=(-3\times -5),(3\times 5)$

so, we can find k

At $(-1\times -15)$ :

$k=a+b$

we can plug values

$k=-1-15$

$k=-16$

At $(1\times 15)$ :

$k=a+b$

we can plug values

$k=1+15$

$k=16$

At $(-3\times -5)$ :

$k=a+b$

we can plug values

$k=-3-5$

$k=-8$

At $(3\times 5)$ :

$k=a+b$

we can plug values

$k=3+5$

$k=8$

So, values of k are

$k=-16,k=-8,k=8,k=16$

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3 years ago

64 1/2 solve in indices

Sergeu [11.5K]

Answer:

1/2

Step-by-step explanation:

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2 years ago