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bazaltina [42]
3 years ago
10

(PLEASE SHOW PICTURES ON HOW TO SOLVE THIS)

Mathematics
1 answer:
son4ous [18]3 years ago
3 0

Answer:

Fred is \frac{17}{24} ft taller than Benny

Step-by-step explanation:

Subtract Benny's height from Fred's height

4 \frac{1}{12} - 3 \frac{3}{8} ( change to improper fractions )

\frac{49}{12} - \frac{27}{8}

The LCM of 12 and 8 is 24 , then

= \frac{49(2)}{12(2)} - \frac{27(3)}{8(3)}

= \frac{98}{24} - \frac{81}{24}

= \frac{17}{24}

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5 more than a number y is -2
Nata [24]

Answer:

y + 5 = -2

Step-by-step explanation:

That would be y + 5 = -2

8 0
3 years ago
Does the table show a direct proportional relationship? If so, what is the constant of proportionality?
lesantik [10]

Answer:

C. Yes, 3.5.

Step-by-step explanation:

If there is a relationship of direct proportionality for every ordered pair of the table, then the constant of proportionality must the same for every ordered pair. The constant of proportionality (k) is described by the following expression:

k = \frac{y}{x} (1)

Where:

x - Input.

y - Output.

If we know that (x_{1}, y_{1}) = (13, 45.5), (x_{2}, y_{2}) = (14, 49) and (x_{3}, y_{3}) = (15, 52.5), then the constants of proportionalities of each ordered pair are, respectively:

k_{1} = \frac{y_{1}}{x_{1}}

k_{1} = \frac{45.5}{13}

k_{1} = \frac{7}{2}

k_{2} = \frac{y_2}{x_2}

k_{2} = \frac{49}{14}

k_{2} = \frac{7}{2}

k_{3} = \frac{y_{3}}{x_{3}}

k_{3} = \frac{52.5}{15}

k_{3} = \frac{7}{2}

Since k_{1} = k_{2} = k_{3}, the constant of proportionality is 3.5.

8 0
3 years ago
I'm really stuck can someone help?
serious [3.7K]
You got it right the yellow highlighted
7 0
2 years ago
50 POINTS please help!<br> quickly<br><br> What is the value of sinX?
Oksanka [162]
Answer letter B. 5 45 / 41
5 0
3 years ago
Find the LCM and solve, it's very very urgent. ​
xeze [42]

Answers:

<h3>1. 1050</h3><h3>2. 1200</h3><h3>3. 1200</h3><h3>4. 3360</h3><h3>5. 1080</h3><h3>6. 480</h3>

please see the attached picture for full solution..

Hope it helps....

Good luck on your assignment...

7 0
3 years ago
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