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2 years ago

I NEED HELP ASAP I WILL MARK YOU BRAINLIEST

Mathematics

1 answer:

mojhsa [17]2 years ago

5 0

Answer:

The angles are said to be linear if they are adjacent to each other after the intersection of the two lines. The sum of angles of a linear pair is always equal to 180°. Such angles are also known as supplementary angles. The adjacent angles are the angles which have a common vertex.

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Anyone know this answer?

damaskus [11]

La of sine:

sinC/c = sinB/b==> sin 37°/8 = sin B/12 ==> sin B = 0.903

arcsinB or sin⁻¹ B = 64.5°, & sin (B°) = sin (180° - B°), then

sin(64.5) = sin(180°-64.5°) ==> B = 64.5° or 115.5°

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2 years ago

Find the surface area. Show al of your work

romanna [79]

Answer:

<h2>SURFACE AREA= 110.59</h2>

Step-by-step explanation:

THE FORMULA TO FINDING THE VOLUME OF A CUBE IS V=A³

SIMPLY PLUGIN 4.8 FOR "A" EQUATION SHOULD LOOK LIKE V=4.8³ AND YOU WILL GET THE SAME ANSWER I DID

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2 years ago

If f(x) = 2(3^x) + 1, what is the value of f(2)? (1) 13 (3) 37 (2) 19 (4) 54

DanielleElmas [232]

54 that’s the answer

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2 years ago

Read 2 more answers

Product of squre of x and cube of y

julsineya [31]

Answer:

x²y³

Step-by-step explanation:

(x²) (y³) = x²y³

Hope it helps!

Have a nice day:)

6 0

1 year ago

Read 2 more answers

Use sigma notation to represent the sum of the first seven terms of the following sequence -4,-6,-8.....

lina2011 [118]

Answer:Answer:

$\sum\left {{7} \atop {1}} \right -n(3+n)$

Step-by-step explanation:

Given the sequence -4,-6,-8..., in order to get sigma notation to represent the sum of the first seven terms of the sequence, we need to first calculate the sum of the first seven terms of the sequence as shown;

The sum of an arithmetic series is expressed as $S_n = \frac{n}{2}[2a+(n-1)d]$

n is the number of terms

a is the first term of the sequence

d is the common difference

Given parameters

n = 7, a = -4 and d = -6-(-4) = -8-(-6) = -2

Required

Sum of the first seven terms of the sequence

$S_7 = \frac{7}{2}[2(-4)+(7-1)(-2)]\\\\S_7 = \frac{7}{2}[-8+(6)(-2)]\\\\S_7 = \frac{7}{2}[-8-12]\\\\\\S_7 = \frac{7}{2} * -20\\\\S_7 = -70$

The sum of the nth term of the sequence will be;

$S_n = \frac{n}{2}[2(-4)+(n-1)(-2)]\\\\S_n = \frac{n}{2}[-8+(-2n+2)]\\\\S_n = \frac{n}{2}[-6-2n]\\\\S_n = \frac{-6n}{2} - \frac{2n^2}{2}\\S_n = -3n-n^2\\\\S_n = -n(3+n)$

The sigma notation will be expressed as $\sum\left {{7} \atop {1}} \right -n(3+n)$ . The limit ranges from 1 to 7 since we are to find the sum of the first seven terms of the series.

3 0

2 years ago