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4 years ago

The diagonal of a cube is 28 cm. Identify the length of an edge. Round to the nearest tenth, if necessary. HELP PLEASE!!

Mathematics

1 answer:

makkiz [27]4 years ago

8 0

Answer:

$16.2\ cm$

Step-by-step explanation:

we know that

The diagonal of a cube is equal to

$D=b\sqrt{3}$

where

b is the length of an edge of the cube

we have

$D=28\ cm$

substitute

$28=b\sqrt{3}$

$b=28/\sqrt{3}=16.2\ cm$

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3 years ago

A rectangle has a length of 20 inches. if its perimeter is 64 inches, what is the area?

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Answer:

$\boxed{ \bold{ \huge{ \boxed{ \sf 240 \: {inches}^{2} }}}}$

Step-by-step explanation:

Given,

Length of a rectangle = 20 inches

Perimeter of a rectangle = 64 inches

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$\boxed{ \sf{perimeter = 2(l + w)}}$

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Move 2w to right hand side and change it's sign

⇒ $\sf{2w = 64 - 40}$

Subtract 40 from 64

⇒ $\sf{2w = 24}$

Divide both sides of the equation by 2

⇒ $\sf{ \frac{2w}{2} = \frac{24}{2} }$

Calculate

⇒ $\sf{w = 12 \: inches}$

Width of a rectangle ( w ) = 12 inches

Now, finding the area of a rectangle having length of 20 inches and width of 12 inches

$\boxed{ \sf{area \: of \: rectangle = length \: \times \: \: width}}$

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⇒ $\sf{area \: of \: rectangle =20 \times 12 }$

Multiply the numbers : 20 and 12

⇒ $\sf{area \: of \: rectangle = 240 \: {inches}^{2} }$

Hence, Area of a rectangle = 240 inches²

Hope I helped !

Best regards!

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3 years ago