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pashok25 [27]
3 years ago
7

Is the set of numbers one 1,5,25 and 125 a geometric sequence

Mathematics
1 answer:
Strike441 [17]3 years ago
6 0
Short answer: Yes.
Each member of the sequence is multiplied by 5 to get to the next member of the sequence.

Find the general equation.
tn = a*5^(n - 1)

Example
t4 = 1*5^(4 - 1)
t4 = 1*5^3
t4 = 125 just as the sequence shows.

t5 = 1^5^4
t5 = 625     Any member of the sequence can be found this way.
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find the midpoint using the formula

(x1+x2)/2 , (y1+y2)/2
x=6 and -2
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(6+2)/2 , (-4+4)/2
8/2 ,0/2
the midpoint is (4,0) A

4 0
3 years ago
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The following functions give the populations of four towns with time tt in years.
expeople1 [14]

Solution :

Transforming given equations :

1)\ P = 600( 1 + \dfrac{12}{100})^t\\\\2)\ P = 1000( 1 + \dfrac{3}{100})^t\\\\3)\ P = 200( 1 + \dfrac{8}{100})^t\\\\4)\ P = 900( 1 - \dfrac{10}{100})^t

From above equations we can see that equation 1) has largest percentage growth rate and the percent growth rate is 12% .

Hence, this is the required solution.

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Find the area of a circle that has a radius of 9 mm. Use 3.14 for π.
melisa1 [442]

Answer: 254,34 mm².

Step-by-step explanation:

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7 0
2 years ago
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Solve these linear equations in the form y=yn+yp with yn=y(0)e^at.
WINSTONCH [101]

Answer:

a) y(t) = y_{0}e^{4t} + 2. It does not have a steady state

b) y(t) = y_{0}e^{-4t} + 2. It has a steady state.

Step-by-step explanation:

a) y' -4y = -8

The first step is finding y_{n}(t). So:

y' - 4y = 0

We have to find the eigenvalues of this differential equation, which are the roots of this equation:

r - 4 = 0

r = 4

So:

y_{n}(t) = y_{0}e^{4t}

Since this differential equation has a positive eigenvalue, it does not have a steady state.

Now as for the particular solution.

Since the differential equation is equaled to a constant, the particular solution is going to have the following format:

y_{p}(t) = C

So

(y_{p})' -4(y_{p}) = -8

(C)' - 4C = -8

C is a constant, so (C)' = 0.

-4C = -8

4C = 8

C = 2

The solution in the form is

y(t) = y_{n}(t) + y_{p}(t)

y(t) = y_{0}e^{4t} + 2

b) y' +4y = 8

The first step is finding y_{n}(t). So:

y' + 4y = 0

We have to find the eigenvalues of this differential equation, which are the roots of this equation:

r + 4 =

r = -4

So:

y_{n}(t) = y_{0}e^{-4t}

Since this differential equation does not have a positive eigenvalue, it has a steady state.

Now as for the particular solution.

Since the differential equation is equaled to a constant, the particular solution is going to have the following format:

y_{p}(t) = C

So

(y_{p})' +4(y_{p}) = 8

(C)' + 4C = 8

C is a constant, so (C)' = 0.

4C = 8

C = 2

The solution in the form is

y(t) = y_{n}(t) + y_{p}(t)

y(t) = y_{0}e^{-4t} + 2

6 0
3 years ago
Math is hard can u help me
Mariana [72]
What do you need? I know many mathematical skills
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