Answer:

And for this case we want a gpa of 3.0 taking in count that in this semester he/ she is going to take 16 credits so then the new mean would be given by:

And we can solve for
and solving we got:

And from the previous result we got:

And solving we got:

And then we can find the mean with this formula:

So then we need a 3.3 on this semester in order to get a cumulate gpa of 3.0
Step-by-step explanation:
For this case we know that the currently mean is 2.8 and is given by:

Where
represent the number of credits and
the grade for each subject. From this case we can find the following sum:

And for this case we want a gpa of 3.0 taking in count that in this semester he/ she is going to take 16 credits so then the new mean would be given by:

And we can solve for
and solving we got:

And from the previous result we got:

And solving we got:

And then we can find the mean with this formula:

So then we need a 3.3 on this semester in order to get a cumulate gpa of 3.0
Idk exactly what your question is asking, but I think you are doing genetics? If you are then you are talking about a punnet square. All four boxes should be heterozygous(Cc). Hope this helps.
The cinnamon would cost $12.80 per pound.
Answer:
C)
Step-by-step explanation:
Prime factorization of 420 = 2 × 2 × 3 × 5 × 7 = 22 × 3 × 5 × 7.
If you take...
2 + 2 + 3 + 5 + 7...
You would get 17.
Hope this helps! :) Good Luck!
<em>-kiniwih426</em>
Answer:
4b+17
Step-by-step explanation:
3(b+5)+b+2=
3b+15+b+2=
4b+17