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Aleonysh [2.5K]
3 years ago
7

What is the answer for this math

Mathematics
1 answer:
dolphi86 [110]3 years ago
3 0

A and C is the answer for the question

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g (15 points) Suppose 42 out of 600 rats exposed to a potential carcinogen develop tumors. A control group of 350 rats not expos
vazorg [7]

Answer:

a) The relative risk is 1.8\overline{846153}

b) The attributable risk is 0.69 \overline{047619}

c) There is a relationship between exposure and tumor risk

Step-by-step explanation:

The number of exposed rats that develop tumors, a = 42

The number of rats exposed to the carcinogen = 600 rats

The number of exposed rats that did not develop tumors, b = 600 - 42 = 558

The number of not exposed rats in the control group = 350 rats

The number of rats that develop tumors in the control group, c = 13 tumors

The number of not exposed rats that did not develop tumors, d = 350 - 13 = 337  rats

a) The relative risk, RR = a/(a + b)/(c/(c + d))

∴ RR = (42/(42 + 558))/(13/(13 + 337)) = 49/26 = 1.8\overline{846153}

b) The attributable risk = (a - c)/a

∴ The attributable risk = (42 - 13)/42 = 0.69 \overline{047619}

c) The odds ratio = (a·b)/(c·d)

∴ The odds ratio = 42 × 558/(13 × 337) = 23439/4381 ≈ 5.35

Given that the result of attributable risk is positive, there is an indication that there is a higher probability to develop tumor when exposed to the potential carcinogen, therefore, there is a relationship between exposure and tumor risk

7 0
3 years ago
In a Create of 30 eggs<br>only 60 % is good how many<br>are bad?<br><br>​
andrew11 [14]

Answer:

In my point of view 40% are bad

5 0
3 years ago
After being rearranged and simplified, which of the following equations could be solved using the quadratic formula?
Alecsey [184]

For this case we must indicate which of the equations shown can be solved using the quadratic formula.

By definition, the quadratic formula is applied to equations of the second degree, of the form:

ax ^ 2+ bx+ c = 0

Option A:

2x ^ 2-3x +10 = 2x + 21

Rewriting we have:

2x ^ 2-3x-2x+ 10-21 = 0\\2x ^ 2-5x-11 = 0

This equation can be solved using the quadratic formula

Option B:

2x ^ 2-6x-7 = 2x ^ 2

Rewriting we have:

2x ^ 2-2x ^ 2-6x-7 = 0\\-6x-7 = 0

It can not be solved with the quadratic formula.

Option C:

5x ^ 2 + 2x-4 = 2x ^ 2

Rewriting we have:

5x ^ 2-2x ^ 2 + 2x-4 = 0\\3x ^ 2 + 2x-4 = 0

This equation can be solved using the quadratic formula

Option D:

5x ^ 3-3x + 10 = 2x ^ 2

Rewriting we have:

5x ^ 3-2x ^ 2-3x + 10 = 0

It can not be solved with the quadratic formula.

Answer:

A and C

4 0
3 years ago
Read 2 more answers
Mitch has 50 pieces of licorice. He shares them equally with his sister.
leonid [27]
50/2=L is the a expression 
7 0
3 years ago
Read 2 more answers
Can someone help me with this problem? 8z when z =12 Evaluating Expressions
Sindrei [870]

Answer:

96

Step-by-step explanation:

8z when 12=z

substitute the z for 112 when doing that multiply 8(12)=96  

8 0
2 years ago
Read 2 more answers
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