a. f(a) =5a+12
we have 1. a=6
Therefore, where ever we find a we'll substitute in 6
f(6) =5(6) +12
6f=30+12
6f=42
so therefore 1. a=6 will match c on the right
2. a=2
f(2) =5(2) +12
2f = 10+12
2f = 22
therefore 2. a=2 will match a on the right
3. a=4
f(4) =5(4) +12
4f=20+12
4f=32
therefore 3. a=4 will match d on the right
4. a=5
f(5) =5(5) +12
5f=25+12
5f=37
therefore 4. a=5 will match b on the right
Probability=number of specific outcomes/total possible outcomes
And the probability of two events happening at the same time is P(1)*P(2), or the product of the probabilities of each event...
In this case:
P(primary color)=3/6=1/2
P(head)=1/2
P(primary and head)=(1/2)(1/2)=1/4
Answer: b and d
Step-by-step explanation:
Since the roots are x=2 and x=6, we can write the equation as
Substituting in the coordinates of the vertex,
So, the equation is
On expanding, we get
Answer:
∠ b = 23°
Step-by-step explanation:
Complementary angles sum to 90° , then
a + b = 90° , that is
67° + b = 90° ( subtract 67° from both sides )
∠ b = 23°
<h2>
Answer with explanation:</h2>
We know that a removable discontinuity occurs when:
The left and the right hand limit of the function exist at a point and are equal but is unequal to the function's value at that point.
Also it is a point on the graph such that it is undefined at that point.
The graph that has a removable discontinuity is attached to the answer.
Since, at x=0 the left hand and the right hand limit of the function exist but the function is not defined at x=0 , since in the graph there is a open circle at x=0 that means that the point is removed from the range.