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bazaltina [42]
4 years ago
7

What type of data is used to explain a relationship

Mathematics
1 answer:
klemol [59]4 years ago
8 0

I don't even know

Step-by-step explanation:

use Google

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The height of a flagpole is one-quarter of the height of a bridge.
DedPeter [7]

Answer:

the height of the flagpole is three fourths the height of the school. the difference in there heights is 4.5 m. what is the height of the school?

----------

Equation:

f = (3/4)s

s-f = 4.5

----

Substitute for "f" and solve for "s":

s-(3/4)s = 4.5

 

(1/4)s = 4.5

s = 4*4.5

s = 18 meters (height of the school)

---------------

Since f = (3/4)s, f = (3/4)(18)

= (3/2)(9)= 13.5 meters (height of the flag pole)

===============================-step explanation: HOPE THIS HELPS

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4 years ago
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Which graph represents a function? <br> Please help me
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Think the 3 graph would be a function the graph the the arrow going straight up.
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3 years ago
Consider all 5 letter "words" made from the full English alphabet. (a) How many of these words are there total? (b) How many of
VARVARA [1.3K]

Answer:

a) There are 11,881,336 of these words in total.

b) There are 7,893,600 of these words with no repeated letters.

c) 896,376 of these words start with an a or end with a z or both

Step-by-step explanation:

Our words have the following format:

L1 - L2 - L3 - L4 - L5

In which L1 is the first letter, L2 the second letter, etc...

There are 26 letters in the English alphabet.

(a) How many of these words are there total?

Each of L1, L2, L3, L4 and L5 have 26 possible options.

So there are 26^{5} = 11,881,336 of these words total

(b) How many of these words contain no repeated letters?

The first letter can be any of them, so L1 = 26.

At the second letter, the first one cannot be repeated, so L2 = L1 - 1 = 25.

At the third letter, nor the first nor the second one can be repeated, so L3 = L1 - 2 = 24

This logic applies until L5

So we have

26-25-24-23-22

In total there are

26*25*24*23*22 = 7,893,600

of these words with no repeated letters.

(c) How many of these words start with an a or end with a z or both (repeated letters are allowed)?

T = T_{1} + T_{2} + T_{3}

T_{1} is the number of words that start with an a and do not end with z. So we have

1 - 26 - 26 - 26 - 25

The first letter can only be a, and the last one cannot be z. So:

T_{1} = 26^{3}*25 = 439,400

T_{2} is the number of words that start with any letter other than a and end with z. So we have

25 - 26 - 26 - 25 - 1

The first letter can be any of them, other than a, and the last can only be z. So:

T_{2} = 26^{3}*25 = 439,400

T_{3} is the number of words that both start with a and end with z. So:

1 - 26 - 26 - 26 - 1

The first letter can only be a, and the last can only be z. The other three letters could be anything. So:

T_{3} = 26^{3} = 17,576

T = T_{1} + T_{2} + T_{3} = 2*439,400 + 17,576 = 896,376

896,376 of these words start with an a or end with a z or both

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Yes it is. You can use the coodinates to find the distance of each side using the distance formula. After that, then you can proceed with 1/2bh.

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