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Brrunno [24]
4 years ago
6

For a particular cable,the radius of the base of the inner layer is 2 millimeters (mm) and the radius of the base of the outer l

ayer is 6 mm.What is the percent of the area of the base pf the outer layer is the area of the inner layer?
Mathematics
1 answer:
andrew11 [14]4 years ago
4 0

Answer:

Step-by-step explanation:

The formula for determining the area of a circle is expressed as

Area = πr²

Where

π is a constant whose value is 3.14

r represents the radius of the circle.

Considering the inner layer

radius = 2 millimeters

Area of base = 3.14 × 2² = 12.56 mm²

Considering the outer layer,

Radius = 6 mm

Area of base = 3.14 × 6² = 113.04 mm²

Percent of the area of the base of the outer layer that is the area of the base of the inner layer is

12.56/113.04 × 100 = 11.1%

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Step-by-step explanation:

Given

3\sqrt{5}\:-\:3\sqrt{11}+2\sqrt{121}-3\sqrt{90}

Required

Simplify the expression

3\sqrt{5}\:-\:3\sqrt{11}+2\sqrt{121}-3\sqrt{90}

Express the square root of 121 as 11

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Express 90 as 9 * 10

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Split the surd to 2

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Express the square root of 9 as 3

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3\sqrt{5}\:-\:3\sqrt{11}+22-9\sqrt{10}

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