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Brrunno [24]
3 years ago
6

For a particular cable,the radius of the base of the inner layer is 2 millimeters (mm) and the radius of the base of the outer l

ayer is 6 mm.What is the percent of the area of the base pf the outer layer is the area of the inner layer?
Mathematics
1 answer:
andrew11 [14]3 years ago
4 0

Answer:

Step-by-step explanation:

The formula for determining the area of a circle is expressed as

Area = πr²

Where

π is a constant whose value is 3.14

r represents the radius of the circle.

Considering the inner layer

radius = 2 millimeters

Area of base = 3.14 × 2² = 12.56 mm²

Considering the outer layer,

Radius = 6 mm

Area of base = 3.14 × 6² = 113.04 mm²

Percent of the area of the base of the outer layer that is the area of the base of the inner layer is

12.56/113.04 × 100 = 11.1%

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3 years ago
An altitude is drawn from the vertex of an isosceles triangle, forming a right angle
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  • 54 in

Step-by-step explanation:

Use Pythagorean to find the missing side x of the triangle.

<u>It is a hypotenuse with other sides 18 in and half of 15 in:</u>

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<u>The perimeter is:</u>

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2 years ago
What is the average of -2.6, 1.8, -3.3, -2.7, 2.2 ?<br> I dont understand this.
olya-2409 [2.1K]
Average = Mean

To find the mean, add up the numbers and divide it by how many numbers there are.

So,  -2.6+1.8+(-3.3)+(-2.7)+2.2=-4.6

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4 0
2 years ago
I NEED HELP PLEASE ASAP !
In-s [12.5K]

The first rule you need to know is

(a^b)^c=a^{bc}

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\dfrac{(x^{25})^{-6}}{(x^{-3})^{48}}=\dfrac{x^{25\cdot(-6)}}{x^{-3\cdot 48}}=\dfrac{x^{-150}}{x^{-144}}

The second rule you need to know is

\dfrac{a^b}{a^c}=a^{b-c}

So, you have

\dfrac{x^{-150}}{x^{-144}}=x^{-150-(-144)}=x^{-150+144}=x^{-6}

4 0
3 years ago
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The seniors on the student council bought a total of 36 plants to use in landscaping the front of the school. They bought some a
Artyom0805 [142]

Answer: B

Step-by-step explanation:

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Plug into y equation

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Y= 16 azaleas

To check

6(16) + 5(20) = 196

96 + 100 = 196

3 0
3 years ago
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