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Yuri [45]
3 years ago
10

Find the values of the measures shown when each value in the data set increases by 25. Mean: 109 Median: 104 Mode: 96 Range: 45

Standard deviation: 3.6
Mathematics
1 answer:
Vikki [24]3 years ago
4 0

Answer:

The new values are as follows:

Mean: 134

Median: 129

Mode: 121

Range=45

Standard Deviation=3.6

Step-by-step explanation:

When a k real number is added to all the elements of the dataset, the new measures of center (mean, median, and mode) are simply found by adding the value k to the previous values. Thus

Mean_{new}=Mean_{old}+k

Here Mean_{old} is 109 and k is 25 thus

Mean_{new}=Mean_{old}+k\\Mean_{new}=109+25\\Mean_{new}=134

Similarly

Median_{new}=Median_{old}+k

Here Median_{old} is 104 and k is 25 thus

Median_{new}=Median_{old}+k\\Median_{new}=104+25\\Median_{new}=129

Also

Mode_{new}=Mode_{old}+k

Here Mode_{old} is 96 and k is 25 thus

Mode_{new}=Mode_{old}+k\\Mode_{new}=96+25\\Mode_{new}=121

When a k real number is added to all the elements of the dataset, the new measures of variation (range and standard deviation) remain the same thus.

Range_{new}=Range_{old}\\Range_{new}=45

Similarly

Standard\ Deviation_{new}=Standard\ Deviation_{old}\\Standard\ Deviation_{new}=3.6

So the new values of mean, median, mode, range, and standard deviation are 134, 129, 121, 45, and 3.6 respectively.

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Answer:

-1, -2

Step-by-step explanation:

Since multiplication by 0 will result in 0, any value of x resulting in 0

(-1+1)(-1+2)=0

0x1=0

(-2+1)(-2+2)=0

-1x0=0

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3 years ago
Write the fraction 4/9 as an equivalent fraction with the given denominator 45​
slega [8]

Answer:

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5 0
3 years ago
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6) The sum of three consecutive numbers is 120.<br> What is the smallest of the three numbers ?
bekas [8.4K]

Answer:

39

Step-by-step explanation:

Let the smallest number be n,

then the three numbers are n, n+1 and n+2

Therefore, n+(n+1)+(n+2)=120

Collecting like terms,

n+n+n=120-1-2

3n=117

n=117/3

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Therefore the numbers are 39,40 and 41.

And the smallest number is 39.

8 0
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(10) Both red line and blue line trains left the station at 5:00 pm. If both
scoundrel [369]

Answer:

5:40

Step-by-step explanation:

This is a problem involving the least common difference.

If you know that the red and blue trains left at the same time at 5, you know that another red train will leave at 5:08. Another blue train at 5:10.

The way to solve this will be to write out the factors of 8 and 10 and find the smallest number that they overlap.

Red:

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Blue:

10, 20, 30, 40

You see that after 40 mnutes, they are both leaving the station again. After 40 minutes, at 5:40, they are both leaving.

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