A 1.5 standard deviation above the mean is
np + 1.5 <span>√(np(1-p))
We are given with
np = 200
p = 200/n
The standard deviation is
</span><span>√200(1-200/n))
Substituting
200 + 1.5 </span>√200(1-200/n))
By inspection, if the value of n is 200, then the radical will result to the value of 1. Only by increasing the value of n greater than 200 will the radical result to a value of less than 1 and decreasing the spread of the mean.
The answer is
the minimum is 201
the maximum is infinity
Answer:
5 x 4 + 2 - 3 / 1
Step-by-step explanation:
Took me a lot of tries but got it! :) Hope this helps
20.75 because if you add 4.85+7.95+7.95 add that you get 20.75
From 100 to 80 is 8/10, so the recursive formula is
an=a(n-1)*1/8
or
an= a1*1/8(n-1)
an=a1*(n-1)/8
