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2 years ago

11

I dint understand this what’s the answer?

1 answer:

attashe74 [19]2 years ago

7 0

The answer I think it is would be B

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Use the following function rule to find f(4).<br><br> f(x) = <br> 5 + <br> 7 <br> x

vladimir2022 [97]

Answer:

33

Step-by-step explanation:

put 4 in for x and then solve

5+7(4)

5+28

33

6 0

3 years ago

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April has 40 cookies to make for upcoming bake sale. she made 3/5 of the cookies chocolate chip and 1/4 of them peanut butter. H

Vikki [24]

30 chocolate chip and 10 peanut butter

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3 years ago

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Lf f(x) = 5x, what is f^-1(x)?

Nonamiya [84]

Answer: $f^{-1}(x)=\frac{x}{5}$

Step-by-step explanation:

By definition the domain of an inverse function $f^-1(x)$ is the range of f(x) and the range of the inverse function is equal to the domain of the principal function f(x).

If you have a function $f(x)=5x$ , then to find the inverse function, follow these steps:

1. Make $y=f(x)$

$f(x)=y=5x$

$y=5x$

2. Solve for the variable "x":

$x=\frac{y}{5}$

3. Exchange the variable "x" with the variable "y":

$y=\frac{x}{5}$

4. Exchange "y" with $f^{-1}(x)$ . Then the inverse function is:

$f^{-1}(x)=\frac{x}{5}$

7 0

3 years ago

For each day that Sasha travels to work, the probability that she will experience a delay due to traffic is 0.2. Each day can be

lions [1.4K]

Answer:

0.8213

Step-by-step explanation:

-This is a binomial probability problem given by the function:

$P(X=x)={n\choose x}p^x(1-p)^{n-x}$

Given that n=21 and p=0.2, the probability that she experience a delay on at least 3 days is calculated as:

$P(X=x)={n\choose x}p^x(1-p)^{n-x}\\\\P(X\geq 3)=1-P(X$

Hence, the probability that she experience delay on at least 3 days is 0.8213

6 0

3 years ago

100 points for correct answer

Tems11 [23]

Answer:

$\dfrac{x}{3}+\dfrac{3}{y}$

Step-by-step explanation:

<u>Given fraction</u>:

$\dfrac{xy+9}{3y}$

$\textsf{Apply the fraction rule} \quad \dfrac{a+b}{c}=\dfrac{a}{c}+\dfrac{b}{c}:$

$\implies \dfrac{xy}{3y}+\dfrac{9}{3y}$

Rewrite 9 as 3 · 3:

$\implies \dfrac{xy}{3y}+\dfrac{3 \cdot 3}{3y}$

Cancel the common factor y in the first fraction and the common factor 3 in the second fraction:

$\implies \dfrac{x\diagup\!\!\!\!y}{3\diagup\!\!\!\!y}+\dfrac{\diagup\!\!\!\!3 \cdot 3}{\diagup\!\!\!\!3y}$

$\implies \dfrac{x}{3}+\dfrac{3}{y}$

7 0

6 months ago