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mrs_skeptik [129]
3 years ago
11

Which of the following is NOT a monomial?

Mathematics
1 answer:
Alexandra [31]3 years ago
3 0

wutz da optionz????????

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Find the perimeter of a rectangle with a length of 6x+3 and a width of -2x-5.
blsea [12.9K]
The simple way of calculating a perimeter is to add all of the sides.
For a rectangle this would equal 2 x length + 2 x width
P = 2(6x + 3) + 2(-2x - 5)
= 12x + 6 - 4x - 10
= 8x - 4

At a higher level both the length and width must be greater than zero (= zero is a trivial rectangle)
6x + 3 > 0
6x > -3
x > -0.5

-2x - 5 > 0
2x + 5 < 0 (multiplying by -1 reverses the inequality)
2x < -5
x < -2.5

This rectangle cannot exist as x cannot be < -2.5 and > -0.5 at the same time!
8 0
3 years ago
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-5/7 - -6/7z &lt; -2/7 how do I make this into a decimal
Xelga [282]
-5/7 - (-6/7)z < -2/7
-5/7 + 6/7z < -2/7
6/7z = -2/7 + 5/7 = 3/7
z = 3/7 / 6/7 = 3/7 x 7/6 = 3/6 = 0.5
z = 0.5
6 0
4 years ago
In the first third of the project Morgan had used 9 gallons of pain
Setler79 [48]
The first answer to the first question is 27
the second answer to the second question is 2,875 million km
the third answer to the third question is <span>31680000</span>
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3 years ago
Help him me I’m new here
Stella [2.4K]

Given:

Composite figure made of cylinder and two spheres.

To find:

The volume of the composite solid.

Solution:

Radius = 2 in

The value of π = 3.14

<u>Volume of sphere:</u>

$V=\frac{4}{3} \pi r^3

$V=\frac{4}{3} \times 3.14 \times 2^3

$V=\frac{4}{3} \times 3.14 \times 8

V=33.49

Volume of a sphere is 33.49 in³

Volume of two spheres = 2 × 33.49 = 66.98 in³

Radius of cylinder = 2 in

Height of cylinder = 8 - 2 - 2 = 4 in

<u>Volume of cylinder:</u>

$V=\pi r^2 h

V = 3.14 × 2² × 4

V = 50.24

Volume of cylinder = 50.24 in³

Volume of composite solid = Volume of two spheres + Volume of cylinder

                                             = 66.98 in³ + 50.24 in³

                                             = 117.2 in³

The volume of the composite solid is 117.2 in³.

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3 years ago
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D shows equivalent expressions
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