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Inga [223]
3 years ago
10

Two different crews earn different amounts for different hours they work.

Mathematics
2 answers:
skelet666 [1.2K]3 years ago
8 0

Answer:

the answer is 120

Step-by-step explanation:

Liula [17]3 years ago
6 0

Answer:

I need to see the graph in order to answer the question

Step-by-step explanation:

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Factor 8q^2 + 3m + 4qm + 6q=
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4q(2q) + 4q(m) + 3(2q) + 3(m)
4q(2q + m) + 3(2q + m)
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8 0
4 years ago
Simplify the following expression.
levacccp [35]
51x+83y-14x-25y=37x+58y
4 0
4 years ago
What is the area of the fire pit? (Use 3.14 for pi.)
laila [671]

Answer:

Area = 65.94

Step-by-step explanation:

I will assume that the shaded region is the fire pit

Given

R = 5

r = 2

Required

Determine the area of the fire pit

First, calculate the area of the big circle.

A_2 = \pi R^2

Area of the small is:

A_1 = \pi r^2

The area of the pit is:

Area = A_2 - A_1

Area = \pi R^2 - \pi r^2

Area = \pi (R^2 -  r^2)

Area = 3.14 (5^2 -  2^2)

Area = 3.14 (25 -  4)

Area = 3.14 * 21

Area = 65.94

5 0
3 years ago
Write an expression describing all the angles that are coterminal with 266°
Softa [21]

Answer:

-814°, -454°, -94°, 266°, 626°. Did you mean like that?

6 0
3 years ago
Two containers, X and Y, are each filled by an ideal gas at the same temperature. The volume of Y is half the volume of X. The n
-Dominant- [34]

Answer:

The answer to the question is

The ratio of the two gas pressures   \frac{P_{x} }{P_{y} } , that is Px to Py = 1/6

Step-by-step explanation:

Let the gases Volumes be V₁ and V₂

Where volume of X = V₁ and

volume of Y = V₂

The volume of Y is half the volume of X

∴ V₂  =  \frac{1}{2} × V₁

Let the number of moles be n₁ and n₂ in X and Y respectively

therefore  n₂ = 3 × n₁

The pressure of the gas in X is Pₓ and the pressure of the gas in Y is  P_{y} then we have

P₁ × V₁  = n₁ × R × T₁ , and P₂ × V₂ = n₂ × R × T₂

(P₁ × V₁)/(n₁ × T₁) = (P₂ × V₂)/(n₂ × T₂)

but T₁ = T₂

Therefore

(P₁ × V₁)/n₁ = (P₂ × V₂)/n₂.  However  n₂ = 3 × n₁  and V₂  =  \frac{1}{2} × V₁ therefore substituting in the equation we have

(P₁ × V₁)/n₁ = (P₂ ×  \frac{1}{2} × V₁ )/(3 × n₁) from where

P₁ /P₂ =  (\frac{1}{2} × V₁ × n₁)/(V₁×3 × n₁) =0.5/3 = 1/6

The ratio of \frac{P_{x} }{P_{y} } = 1/6

6 0
4 years ago
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