<span>Total lot - house -other side
=(56 ft 9 in) - (34 ft 10 in) - (5 ft 5 in)
=(55 ft 21 in) - (34 ft 10 in) - (5 ft 5 in)
=16 ft 6 in
Convert to inches: </span>16 ft x 12 in/ft)+ 6 in= Total in inches<span>192 in + 6 in= Total in inches
198 in= Total in inches
Check: One side + house + other side = Lot width
(5 ft 5 in)+(34 ft 10 in)+(16 ft 6 in)=Lot width
56 ft 9 in=Lot width, which equals the given.</span>
Answer: Chuck's travel at a rate of 52mph
Step-by-step explanation:
For Chuck's trip:
D=RT
104= (R+4)T
T= 104 / (R+4)
For Dana's trip:
96 = RT
T= 96/R
Set both equation for Chuck's and Dana together
104/(R+4) =96/R
Then we cross multiply
96(R+4) = 104R
96R + 384 = 104R
104R - 96R = 384
8R = 384
To get R, divide both side by 8
8R/8 = 384/8
R= 48mph
This means Dana's speed is 48mph
Chuck's speed will be: 48mph+4mph = 52mph
X+y=9
y=8x
x+8x= 9
9x = 9
x = 9/9
x = 1
y = 8(1)
y =8
Answer:
4 ft 2 in.
Step-by-step explanation:
A door to a playhouse is 50 inches tall
we know that
1 in---------------> is 0.0833333 ft
so
50 in-------------> 50*0.0833333---------> 4.167 ft
4.167 ft----------> [4 ft+0.167 ft]
remember that
1 in---------------> is 0.0833333 ft
X in----------------> 0.167 ft
X=0.167/0.0833333----------> X=2 in
4.167 ft----------> [4 ft+0.167 ft]--------> [4 ft+2 in]
