Answer:
The point of intersection of the two lines is;
(-9,-2)
Step-by-step explanation:
What we have to here is to get the equation of both lines, solve simultaneously and get the intersection points
For the first line;
The general form is
y = mx + b
formula for the slope is;
m = (y2-y1)/(x2-x1)
The points (3,4) and (-1,2)
m = (2-4)/(-1-3) = -2/-4 = 1/2
So the equation is;
y = 1/2x + b
To get b, let us substitute coordinates of the first point;
4 = 1/2 * 3 + b
4 = 3/2 + b
b = 4 - 3/2
b = (8-3)/2 = 5/2
So the equation is;
y = 1/2x + 5/2
For the second line;
Slope;
m = (-4-0)/(-6+12) = -4/6 = -2/3
The equation is;
y = -2x/3 + b
Let us substitute the first
0 = -2/3(-12) + b
0 = 8 + b
b = -8
The equation is;
y = -2x/3 - 8
Now , we want to get the intersection point
To do this, we have to solve both equations simultaneously;
Since we have an expression for y in both cases, let us equate both y
-2x/3-8 = 1/2x + 5/2
Multiply through by 6
-4x - 48 = 3x + 15
-4x-3x = 15 + 48
-7x = 63
x = 63/-7
x = -9
To get x;
Recall;
y = -2x/3 - 8
y = -2/3(-9) - 8
y = 6 - 8
y = -2
