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den301095 [7]
2 years ago
6

Does anybody know what the answer to this question is?

Mathematics
1 answer:
crimeas [40]2 years ago
7 0

Answer:

equation 15+8=

solution= 23

Step-by-step explanation:

its ez

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What is the domain of the following graph? Please don't put links down I cant download them.
rosijanka [135]

Answer:

-infinity, infinity

Step-by-step explanation:

Domain is x, and in a quadratic equation like this one the x axis goes on forever. So the first answer of -infinity, infinity is correct.

8 0
2 years ago
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Y is inversely proportional to x, when Y = 2, x = 4.
irina [24]

Answer:

Constant of proportionality is y divided by x.  y is 2 and x is 4.  2 divided by 4 is 1/2.

Let me know if that is correct.

Step-by-step explanation:

6 0
3 years ago
-20 = -4x - 6x<br> I need help solving it
eduard

Answer:

the answer is 2

Step-by-step explanation:

add -4x and -6x and the answer is -10x bc they are both negative x. then divide both -10x and -20 by -10 so that it is x by itself on one side and 2 on the other so its 2=x :)

6 0
3 years ago
F(x) = <img src="https://tex.z-dn.net/?f=%5Csqrt%7Bx%2B7%7D%20-%5Csqrt%7Bx%5E2%2B2x-15%7D" id="TexFormula1" title="\sqrt{x+7} -\
elena-s [515]

Answer:

x >= -7  ................(1a)

x >= 3   ...............(2a1)

Step-by-step explanation:

f(x) =  \sqrt{x+7}-\sqrt{x^2+2x-15}  .............(0)

find the domain.

To find the (real) domain, we need to ensure that each term remains a real number.

which means the following conditions must be met

x+7 >= 0  .....................(1)

AND

x^2+2x-15 >= 0 ..........(2)

To satisfy (1),  x >= -7  .....................(1a) by transposition of (1)

To satisfy (2), we need first to find the roots of (2)

factor (2)

(x+5)(x-3) >= 0

This implis

(x+5) >= 0 AND (x-3) >= 0.....................(2a)

OR

(x+5) <= 0 AND (x-3) <= 0 ...................(2b)

(2a) is satisfied with x >= 3   ...............(2a1)

(2b) is satisfied with x <= -5 ................(2b1)

Combine the conditions (1a), (2a1), and (2b1),

x >= -7  ................(1a)

AND

(

x >= 3   ...............(2a1)

OR

x <= -5 ................(2b1)

)

which expands to

(1a) and (2a1)   OR  (1a) and (2b1)

( x >= -7 and x >= 3 )  OR ( x >= -7 and x <= -5 )

Simplifying, we have

x >= 3  OR ( -7 <= x <= -5 )

Referring to attached figure, the domain is indicated in dark (purple), the red-brown and white regions satisfiy only one of the two conditions.

3 0
3 years ago
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Don't mind this.......
DIA [1.3K]

Answer:

okay thank you for free points

4 0
3 years ago
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