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olga_2 [115]
3 years ago
5

In your last 24 basketball games, you attempted 93 free throws and made 69. Find the experimental probability that you make a fr

ee throw. Write the probability as a percent, to the nearest tenth of a percent.
74.2%

70.5%

77.2%

72.9%
Mathematics
1 answer:
Dafna11 [192]3 years ago
8 0
For this problem you only need to look at two numbers out of the three that are given the number of basketball games is irrelevant . So why you want to do is divid the number of made shots by the number of attempted shots
69/93 and when the division is done you get .7419 then you shift the decimal point over two to the right and get 74.19% and round to the nearest tenth makes it so you get 74.2 %
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I believe the answer would be 3/40
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Which situation can be represented by the expression 5−8
Iteru [2.4K]

Answer:

The answer is C.)

Step-by-step explanation:

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2 years ago
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For each of the -3.3 trials, and in the same sequence in which you entered the freezing points, enter your calculated values for
dedylja [7]

Answer:

The morality of the solution is calculated as 0.859 m. We are required to determine the freezing point depression constant of pure water. The freezing point depression of the solution is given as

T_{f}  = T_{p}  -T_{s} = K_{f} * (morality of solution)

T_{p} and T_{s} are the freezing points of the pure solvent (water, 0°C) andK_{f} = freezing point depression constant of water. Therefore,

T_{f}  = K_{f} *(0.859 m)

=====> (0°C) – (3.00°C) = K_{f}  *(0.859 m)

=====> -3.00°C = K_{f}  *(0.859 m)

Ignore the negative sign (since K_{f} is positive) and get

K_{f} = (3.00°C) / (0.859 m) = 3.492°C/m

The freezing point depression constant of the solvent is 3.5°C kg/mole  

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3 0
2 years ago
Turn .055 into fraction
Slav-nsk [51]
Write 0.055 as
0.055
1

Multiply both the numerator and denominator by 10 for each digit after the decimal point.

0.055
1

The factors of 55 are: 1 5 11 55
The factors of 1000 are: 1 2 4 5 8 10 20 25 40 50 100 125 200 250 500 1000
The Greatest Common Factor (GCF) for both 55 and 1000 is: 5
Now to reduce the fraction we divide both the numerator and denominator by the GCF value.

=
0.055 x 1000
1 x 1000
=
55
1000


In order to reduce the fraction find the Greatest Common Factor (GCF) for 55 and 1000. Keep in mind a factor is just a number that divides into another number without any remainder.

Answer ( 55/1000
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8 0
2 years ago
A study of homeowners in the 5th congressional district in Maryland found that their annual household incomes are normally distr
tino4ka555 [31]

Answer:

The minimum income level for this target group is of $51,253.6.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of $41,182 and a standard deviation of $11,990

This means that \mu = 41182, \sigma = 11990

Find the minimum income level for this target group.

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Z = \frac{X - \mu}{\sigma}

0.84 = \frac{X - 41182}{11990}

X - 41182 = 0.84*11990

X = 51253.6

The minimum income level for this target group is of $51,253.6.

4 0
3 years ago
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