DB/dt = 1/5(100 - B)
5/(100 - B) dB = dt
-5 ln (100 - B) = t + C
Since B(0) = 20, then
-5 ln (100 - 20) = C
i.e. C = -5 ln 80
Thus -5 ln (100 - B) = t - 5 ln 80
or t = 5 ln 80 - 5 ln (100 - B) = 5 ln (80 / (100 - B))
When the weight = 40 grams
t = 5 In (80 / 100 - 40) = 5 In (80 / 60) = 5 ln (4/3) = 1.438 days
Rate of weight gain = 40 / 1.438 = 27.8 grams per day
When the weight = 70 grams
t = 5 ln (80 / 100 - 70) = 5 ln (80 / 30) = 5 ln (8/3) = 4.9 days
Rate of weight gain = 70/4.9 = 14.27 grams per day.
Therefore, the duck gains weight faster when it weighs 40 grams.
Answer:
It is unlikely
Step-by-step explanation:
The probability of a sticky dart landing in the green section of the board, assuming that it lands on the board is possible but very unlikely.
The green section of the board has the least area compare to an other section of the board. Therefore, the dark is unlikely to land in this section.
5=60 I think that’s correct
Answer:
4 - 0 = 4
Step-by-step explanation:
The distance is 4 units from 0 to 4
